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2 years ago

What is the molarity when 500mL H2O is added to 20mL 6.0M HNO3?

Chemistry

1 answer:

ss7ja [257]2 years ago

5 0

Answer:

50.00-mL volumetric flask and diluted to the mark with water. What is the molarity of the new solution? 12. 30.00 mL of water is added to 20.00 mL of 0.0500

Explanation:

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~Zero

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What kind of property is melting point? an atomic property , , , an atomic property , , a physical property , a physical propert

jok3333 [9.3K]

Answer:

physical property has a melting point

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2 years ago

The town of Natrium, West Virginia, derives its name from the sodium produced in the electrolysis of molten sodium chloride (NaC

Alona [7]

Explanation:

The reaction equation will be as follows.

$Na^{+} + e^{-} \rightarrow Na(s)$

Hence, moles of Na = moles of electron used

Therefore, calculate the number of moles of sodium as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{4500 g}{23 g/mol}$ (as 1 kg = 1000 g)

= 195.65 mol

As, Q = $n \times F$ where F = Faraday's constant

= $195.65 mol \times 96500 C$

= $1.88 \times 10^{7}$ mol C

Relation between electrical energy and Q is as follows.

E = $Q \times V$

Hence, putting the given values into the above formula and then calculate the value of electricity as follows.

E = $Q \times V$

= $1.88 \times 10^{7} \times 5$

= $9.4 \times 10^{7} J$

As 1 J = $2.77 \times 10^{-7}$ kWh

Hence, $\frac{9.4 \times 10^{7}}{2.77 \times 10^{-7}}$ kWh

= 3.39 kWh

Thus, we can conclude that 3.39 kilowatt-hours of electricity is required in the given situation.

7 0

3 years ago

Read 2 more answers

A county creates an park to protect a forest.

Hatshy [7]

Great for the ecosystem

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3 years ago

A scientist has a container with a substance inside. At first, the molecules in the substance move away from each other. Later,

Vera_Pavlovna [14]

Answer:

Base on the properties the substances possess the substance change phase from gas to liquid.

Explanation:

Generally, matter can exist in three phase namely liquid , solid and gas. The scientist has a container with a substance inside.

At first the substance moves away from each other . This means the substance was first in the gas phase . Gas molecules, because of the energy they possess , it can move rapidly and randomly and most at times move away from each other . The gas molecules tends to fill the whole volume of the container and the shape of gases are indefinite.

Later the molecules move around each other. This is a property of a liquid . A substance in liquid phase have the ability to move freely but they stay together because of the force of attraction holding them together . The substance only have the ability to move around each other because the forces holding them together won't allow them to move apart.

Base on the properties the substances possess the substance change phase from gas to liquid.

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3 years ago

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How many cubic centimeters of an ore containing only 0.22% gold (by mass) must be processed to obtain $100.00 worth of gold? The

bezimeni [28]

Answer:

The cubic centimetres of the ore containing 0.22% gold (by mass) that must be processed to obtain the $100.00 worth of gold is approximately 216 cm³

Explanation:

The percentage by mass of gold in the ore = 0.22%

The density of the ore = 8.0 g/cm³

The price of the gold = $818 per troy ounce

14.6 troy oz = 1.0 pound

1 lb = 454 g

Given that one troy ounce = $818

$100 worth of gold = 1/818 ×100 troy ounce = 100/818 troy ounce

1 troy oz = 1.0/14.6 lb

100/818 troy oz = 100/818 × 1.0/14.6 lb = 250/29857 lb ≈ 0.0084 lb

1 lb = 454 g

250/29857 lb = 454 × 250/29857 g ≈ 3.8015 g

$100 = 3.8015 g worth of gold

The mass, M, of the ore containing 3.8015 g of gold is given as follows;

0.22% of M = 3.8015 g

0.22/100 × M = 3.8015 g

M = 3.8015 g × 100/0.22 = 1727.933 g

The volume, V, of the ore containing 3.8015 g of gold is given as follows;

Density of ore = Mass of ore/(Volume of ore)

Volume of ore = Mass of ore /(Density of ore)

The density of the ore = 8.0 g/cm³

Volume of ore = 1727.933 g /(8.0 g/cm³) = 215.99 cm³ ≈ 216 cm³

Therefore, the cubic centimetres of the ore containing 0.22% gold (by mass) that must be processed to obtain the $100.00 worth of gold ≈ 216 cm³.

5 0

3 years ago