The answer mass of copper sulphate is
46g
According of Dalton's law of Partial pressure, the total pressure of a mixture of gases is the sum of the partial pressures of the individual vases in the mixture.
Hence;
The for hydrogen collected over water, we have a mixture of hydrogen gas and water vapour.
Total pressure = pressure of hydrogen gas + vapour pressure of water
Pressure of hydrogen gas = Total pressure - vapour pressure of water
Pressure of hydrogen gas = 636 mmHg - 28.3 mmHg
Pressure of hydrogen gas = 607.7 mmHg
The shape of the molecule is trigonal planar.
For example, H₂O:
..
O
/ \
H H
Answer:
[COF₂] = 0.346M
Explanation:
For the reaction:
2COF₂(g) ⇌ CO₂(g) + CF₄(g)
Kc = 5.70 is defined as:
Kc = [CO₂] [CF₄] / [COF₂]² = 5.70 <em>(1)</em>
Equilibrium concentrations of each compound after addition of 2.00M COF₂ will be:
[COF₂] : 2.00M - 2x
[CO₂] : x
[CF₄] : x
Replacing in (1):
5.70 = [X] [X] / [2-2x]²
22.8 - 45.6x + 22.8x² = x²
0 = -21.8x² + 45.6x - 22.8
Solving for x:
X = 1.265 <em>-False answer, will produce negative concentrations-</em>
<em>X = 0.827.</em>
Replaing, molar concentration of COF₂ is:
[COF₂] : 2.00M - 2×0.827 = <em>0.346M</em>
I hope it helps!
Answer:
a) 381.2 g
b) 39916 g
c) 0.0013 lb mol
d) 29.6 g mol
Explanation:
The molecular weight (mw) of a compound is the mass of it per mole, so it's the ratio of the mass (m) per mole (n).
a) The molecular weight of one mol is found at the periodic table. So, for Mg, mw = 24.3 g/mol, for Cl = 35.5 g/mol, so for MgCl2, mw = 24.3 + 2*35.5 = 95.3 g/mol. The g mol is the mass divided by the molecular weight:
g mol = m/mw
4 = m/95.3
m = 381.2 g
b) The pound (lb) is a unity of mass, and the lb mol is a unity of the mass divided by the molecular weight. So, by the periodic table, the molecular weight of C3H8 is 3*12 (of C) + 8*1 (of H) = 44 lb/mol.
lb mol = m/mw
2 = m/44
m = 88 lb
1 lb = 453.592 g
So, m = 88*453.592 = 39916 g
c) The molecular weight of N2 is 2*14 (of N) = 28 lb/mol.
m = 16/453.592 = 0.0353 lb
lb mol = m/mw
lb mol = 0.0353/28
lb mol = 0.0013 lb mol
d) The molecular weight is 2*12 (of C) + 6*1(of H) + 1*16(of O) = 46 g/mol
3 lb = 1360.78 g
g mol = m/mw
g mol = 1360.78/46
g mol = 29.6 g mol
