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Similarities:
-They can conduct electric current because they both are ionic substances.-
-They both form Water and Salt when neutralized.
Differences:
-Acids release Hydronium ions (H₃O⁺) when hydrolyzed while Bases release Hydroxyl ions (OH⁻) when hydrolyzed.
-Acids are commonly formed with non-metals (such as Chlorine, Sulfur, Oxygen, and Nitrogen) while Bases are commonly formed with metals (such as Sodium, Potassium, Calcium, and Copper).
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Answer:
5 moles of Fe₂(SO₄)₃ will be produced
Explanation:
Given data:
Number of moles of Fe₂(SO₄)₃ = ?
Number of moles of Fe react = 10 mol
Solution:
Chemical equation:
3H₂SO₄ + 2Fe → Fe₂(SO₄)₃ + 3H₂
Now we will compare the moles of iron and Fe₂(SO₄)₃ .
Fe : Fe₂(SO₄)₃
2 : 1
10 : 1/2×10 = 5 mol
5 moles of Fe₂(SO₄)₃ will be produced.
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Answer:
See explanation
Explanation:
Usually, when we write a chemical formula for any compound or other chemical specie, we use subscripts to;
- Indicate the ratio of atoms of each element present in the compound or chemical specie
- Show the number of atoms of each element present in the compound or chemical specie.
Hence, the subscripts written after chemical formulas have more than one function as described above.
In H2SO4 for instance, there are two hydrogen atoms, one sulphur atom and four oxygen atoms as shown in the chemical formula.
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Answer:</h3>
2.125 g
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Explanation:</h3>
We have;
- Mass of NaBr sample is 11.97 g
- % composition by mass of Na in the sample is 22.34%
We are required to determine the mass of 9.51 g of a NaBr sample.
- Based on the law of of constant composition, a given sample of a compound will always contain the sample percentage composition of a given element.
In this case,
- A sample of 11.97 g of NaBr contains 22.34% of Na by mass
A sample of 9.51 g of NaBr will also contain 22.345 of Na by mass
% composition of an element by mass = (Mass of element ÷ mass of the compound) × 100
Mass of the element = (% composition of an element × mass of the compound) ÷ 100
Therefore;
Mass of sodium = (22.34% × 9.51 g) ÷ 100
= 2.125 g
Thus, the mass of sodium in 9.51 g of NaBr is 2.125 g