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Wittaler [7]
2 years ago
15

Describe how sponges reproduce

Chemistry
1 answer:
Natali5045456 [20]2 years ago
5 0
They can reproduce in 3 ways: budding, gemmules, and regeneration.
Budding- a new sponge grows off of the older ones eventually breaking off.
Gemmules- internal buds found in sponges. The mass of cells get bigger and bigger and eventually form an adult sponge
Regeneration- sponges are able to restore damaged or broken parts.
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SVEN [57.7K]
Not me but that’s wsp
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The space shuttle___.
Len [333]

Answer:

goes very fast and carries astronauts

Explanation:

5 0
3 years ago
A 12.0% sucrose solution by mass has a density of 1.05 gem, what mass of sucrose is present in a 32.0-mL sample of this solution
natulia [17]

Answer:

Option C. 4.03 g

Explanation:

Firstly we analyse data.

12 % by mass, is a sort of concentration. It indicates that in 100 g of SOLUTION, we have 12 g of SOLUTE.

Density is the data that indicates grams of solution in volume of solution.

We need to determine, the volume of solution for the concentration

Density = mass / volume

1.05 g/mL = 100 g / volume

Volume =  100 g / 1.05 g/mL → 95.24 mL

Therefore our 12 g of solute are contained in 95.24 mL

Let's finish this by a rule of three.

95.24 mL contain 12 g of sucrose

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7 0
3 years ago
What is the hybridization of carbon in nco-?
Svet_ta [14]

First let us see what kind of bonds are formed in the compound. By drawing the structure, we see that the kind of bonds are:

N =- triple bond -= C – O

<span>So there is only single bond between C and O therefore the hybridization of C is sp.</span>

4 0
3 years ago
Read 2 more answers
When 0.49 g of a molecular compound was dissolved in 20.00 g of cyclohexane, the freezing point of the solution was lowered by 3
IRISSAK [1]

Answer: The molecular mass of this compound is 131 g/mol

Explanation:

Depression in freezing point:

\Delta T_f=i\times k_f\times \frac{w_2\times 1000}{M_2\times w_1}

where,

\Delta T_f = depression in freezing point  = 3.9^oC

k_f = freezing point constant  = 20.8^0C/m

m = molality

i = Van't Hoff factor = 1 (for non-electrolyte)

w_2 = mass of solute = 0.49 g

w_1 = mass of solvent (cyclohexane) = 20.00 g

M_2 = molar mass of solute = ?

Now put all the given values in the above formula, we get:

(3.9)^oC=1\times (20.8^oC/m)\times \frac{(0.49g)\times 1000}{M_2\times (20.00g)}

M_2=131g/mol

Therefore, the molar mass of solute is 131 g/mol

7 0
2 years ago
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