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3 years ago

What is the equation for the reaction of magnesium and iron 2 oxide

Chemistry

2 answers:

Pepsi [2]3 years ago

8 0

Maybe

Mg+Fe2O3→Fe+MgO

hope it helps

professor190 [17]3 years ago

4 0

Mg + Fe₂O₃ = Fe + MgO

Must click thanks and mark brainliest

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Using the following equation 5KNO2+2KMnO4+3H2SO4=5KNO3+2MnSO4+K2SO4+3H20. Starting with 2.47 grams of KNO2 and excess KMnO4 how

Aleonysh [2.5K]

Given equation : $5KNO_{2} + 2KMnO_{4} + 3H_{2}SO_{4}\rightarrow 5KNO_{3} + 2MnSO_{4} + K_{2}SO_{4} + 3H_{2}O$

Given information = 2.47 grams KNO2 and excess KMnO4 and we need to find grams of water (H2O).

Since KMnO4 is in excess, so grams of water(H2O) can be calculated using grams of KNO2 with the help of stoichiometry.

To find grams of water(H2O) from grams of KNO2 , we need to follow three steps.

Step 1. Convert 2.47 grams of KNO2 to moles of KNO2.

$Moles = \frac{grams}{molar mass}$

Molar mass of KNO2 = 85.10 g/mol

$Moles = 2.47 gram KNO2\times \frac{1 mol KNO2}{85.10 gram KNO2}$

Moles = 0.0290 mol KNO2

Step 2. Convert moles of KNO2 to moles of H2O using mole ratio.

Mole ratio are the coefficient present in front of the compound in the balanced equation.

Mole ratio of KNO2 : H2O is 5 : 3 (5 coefficient of KNO2 and 3 coefficient of H2O)

$0.0290 mol KNO2\times \frac{3 mol H2O}{5 mol KNO2}$

Mole = 0.0174 mol H2O

Step 3. Convert mole of H2O to grams of H2O

Grams = Moles X molar mass

Molar mass of H2O = 18.00 g/mol

$Grams = 0.0174 mol H2O\times \frac{18 g H2O}{1 mol H2O}$

Grams of water = 0.313 grams H2O

Summary : The above three steps can also be done in a singe setup as shown below.

$2.47 gram KNO2\times \frac{(1 mol KNO2)}{(85.10 gram KNO2)}\times \frac{(3 mol H2O)}{(5 mol KNO2)}\times \frac{(18.00 gram H2O)}{(1mol H2O)}$

In the above setup similar units get cancelled out and we will get grams of H2O as 0.313 grams water (H2O)

8 0

4 years ago

What would be an example of a land form from magma?

notsponge [240]

An example of a land form from magma is B. Lava Plateau.

6 0

4 years ago

Calculate the volume of 6 M acetic acid needed to prepare 100 mL of a 0.10 M acetic acid (CH3COOH) solution.

Zina [86]

Answer:

V = 1.66mL acetic acid

Explanation:

dilution formula:

V1*C1 =V2*C2

⇒ V1*(6M) = (100mL)*(0.1M)

⇒ V1 =( (100mL) * (0.1M) ) / (6M)

⇒ V1 = 1.66mL acetic acid

8 0

3 years ago

Which of the following characteristics indicates that an atom is unstable?

elena55 [62]

Answer:

Explanation:

An atom can be considered unstable in one or two ways. If it pickes up or loses an electron,it becomes electrically charged and highly reactive.Intabability can also occur in the nucleus when the number of protons and neutrons is unbalanced.

8 0

3 years ago

Read 2 more answers

7) Andre added 25mL of water to 75mL of a 5.0M stock solution to make 10 points

valina [46]

Answer:

The concentration of the diluted solution is 3.75 M

Explanation:

Step 1: Data given

Volume of a stock solution = 75 mL = 0.075 L

The molarity of stock solution = 5.0 M

We add 25 mL, The total volume is 100 mL = 0.100 L

Step 2: Calculate the concentration of the diluted solution

C1*V1 = C2*V2

⇒with C1 = the initial concentration = 5.0 M

⇒with V1 = the initial volume = 0.075 L

⇒with C2 = the new concentration = TO BE DETERMINED

⇒with V2 = the diluted volume = 0.100 L

5.0 M * 0.075 L = C2 * 0.100L

C2 = (5.0M * 0.075 L) / 0.100 L

C2 = 3.75 M

The concentration of the diluted solution is 3.75 M

5 0

3 years ago