<span>At time t1 = 0 since the body is at rest, the body has an angular velocity, v1, of 0. At time t = X, the body has an angular velocity of 1.43rad/s2. Since Angular acceleration is just the difference in angular speed by time. We have 4.44 = v2 -v1/t2 -t1 where V and t are angular velocity and time. So we have 4.44 = 1.43 -0/X - 0. Hence X = 1.43/4.44 = 0.33s.</span>
Answer:
51
Explanation:
to keep it simple here is practically how i got it
340x.15=51
Answer:
Explanation:
To the atomic mass;
1. Atomic mass is the number of protons + neutrons;
When a new proton is added, the atomic mass increases.
When a proton is removed, the atomic mass reduces
The mass of an atom is concentrated in the nucleus where there is the proton and neutron.
2. Atomic number is the number of protons:
When a new proton is added, the atomic number increases
When a new proton is removed, the atomic number reduces
3. Charge:
An atom is neutral if the number of positive charges is the same as negative charges:
Protons = electrons
If :
Protons > electrons = +Ve charges
Protons < electrons = -Ve charges
Answer:
The acceleration that the jet liner that must have is 2.241 meters per square second.
Explanation:
Let suppose that the jet liner accelerates uniformly. From statement we know the initial (
) and final speeds (
), measured in meters per second, of the aircraft and likewise the runway length (
), measured in meters. The following kinematic equation is used to calculate the minimum acceleration needed (
), measured in meters per square second:
If we know that 
, 
and 
, then the acceleration that the jet must have is:
The acceleration that the jet liner that must have is 2.241 meters per square second.
Answer:
The height is "89.61 m". A further explanation is given below.
Explanation:
According to the question,
Mass of rocket,
m = 5 kg
Time,
t = 4.6 s
Initial speed of rod
u = o m/s
Final speed,
v = 39 m/s
drag,
= 60 N
So,
⇒ acceleration, 
⇒ 
Now,
The thrust will be:
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
The height will be:
⇒ 
