Answer:
B = 1.3734*10^-7 T
Explanation:
I'm going to take a shot at this since I doubt anyone else would, but I might be wrong, so keep that in mind. Okay, with that out of the way, we know the equation for capacitance:
We also know that it is put in series with a resistor. Since it is initially uncharged and is in series with a battery, it is step response. Using KVL, we will get:
We also know from Ampere's law, there is a magnetic field because of the current induced (right hand rule). From this we can calculate the magnetic field using a contour integral. We can simplify and avoid using Biot-Savart law by using the path of integration of a circle, thus:
Okay now we got all that out of the way, lets first find the area of the plates so we can use the first equation to get capacitance.
Now we need to calculate the current through the capacitor. To do this, use the step response to calculate the voltage drop across the capacitor and then use KVL calculate the current through the resistor. So:
Finally Ampere's law:
B = 1.3734*10^-7 T
Explanation:
Hi Linda,
How's it going?
Sorry I haven't been in touch for such a long time but I've had exams so I've been studying every free minute. Anyway, I'd love to hear all your news and I'm hoping we can get together soon to catch up. We just moved to a bigger flat so maybe you can come and visit one weekend?
How's the new job?
Looking forward to hearing from you!
Helga
Speed is how fast and object moves and velocity is a variable that tells you both speed and direction
Answer:
lauda and lasan I am fine with me lit Q ans pg-14
Answer:
the sound intensity level for actual intensity ( without the earplugs ) is 103.8 dB
Explanation:
Given the data in the question;
sound intensity reduced by the factor, m = 305
the sound intensity level experienced by the crew members wearing protective earplugs, L = 79 dB
Now, using the expression of sound intensity level;
L = 10log( )
where is the intensity at L level
so we substitute
79 = 10log( )
=
Now, expression for actual intensity;
= m
where is the actual intensity
so we substitute
= 305 ×
Next, we write the expression of sound intensity level for reduced intensity;
L' = 10log( )
So we substitute
L' = 10log( 305 × )
L' = 10log( 24227011159.09058 )
L' = 103.8 dB
Therefore, the sound intensity level for actual intensity ( without the earplugs ) is 103.8 dB