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1 year ago

The diagram shows a wave moving from one medium to another

Physics

1 answer:

Shtirlitz [24]1 year ago

3 0

As the speed of wave decreases, the wavelength of the wave decreases.

<h3>Refraction</h3>

We know that as a wave travels from one medium to another its speed decreases depending on if the first medium is less dense than the second medium or increases depending on if the first medium is more dense than the second medium. This is known as refraction

Now, we know that the speed of a wave v = fλ where

f = frequency and
λ = wavelength. Since f is constant, v ∝ λ.

The ratio of the speed in medium one to speed in medium two is called the refractive index of medium 1 to 2.

<h3>Explaining the diagram</h3>

From the diagram, we see that the wavelength in medium 1 is longer than that in medium 2. Since wavelength and speed are proportional, so the speed in medium 1 is also greater than the speed in medium 2.

So, As the speed of wave decreases, the wavelength of the wave decreases.

Learn more about refraction here:

brainly.com/question/25758484

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Missing details: figure of the problem is attached.

We can solve the exercise by using Poiseuille's law. It says that, for a fluid in laminar flow inside a closed pipe,

$\Delta P = \frac{8 \mu L Q}{\pi r^4}$

where:

$\Delta P$ is the pressure difference between the two ends

$\mu$ is viscosity of the fluid

L is the length of the pipe

$Q=Av$ is the volumetric flow rate, with $A=\pi r^2$ being the section of the tube and $v$ the velocity of the fluid

r is the radius of the pipe.

We can apply this law to the needle, and then calculating the pressure difference between point P and the end of the needle. For our problem, we have:

$\mu=0.001 Pa/s$ is the dynamic water viscosity at $20^{\circ}$

L=4.0 cm=0.04 m

$Q=Av=\pi r^2 v= \pi (1 \cdot 10^{-3}m)^2 \cdot 10 m/s =3.14 \cdot 10^{-5} m^3/s$

and r=1 mm=0.001 m

Using these data in the formula, we get:

$\Delta P = 3200 Pa$

However, this is the pressure difference between point P and the end of the needle. But the end of the needle is at atmosphere pressure, and therefore the gauge pressure (which has zero-reference against atmosphere pressure) at point P is exactly 3200 Pa.