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2 years ago

The diagram shows a wave moving from one medium to another

Physics

1 answer:

Shtirlitz [24]2 years ago

3 0

As the speed of wave decreases, the wavelength of the wave decreases.

<h3>Refraction</h3>

We know that as a wave travels from one medium to another its speed decreases depending on if the first medium is less dense than the second medium or increases depending on if the first medium is more dense than the second medium. This is known as refraction

Now, we know that the speed of a wave v = fλ where

f = frequency and
λ = wavelength. Since f is constant, v ∝ λ.

The ratio of the speed in medium one to speed in medium two is called the refractive index of medium 1 to 2.

<h3>Explaining the diagram</h3>

From the diagram, we see that the wavelength in medium 1 is longer than that in medium 2. Since wavelength and speed are proportional, so the speed in medium 1 is also greater than the speed in medium 2.

So, As the speed of wave decreases, the wavelength of the wave decreases.

Learn more about refraction here:

brainly.com/question/25758484

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What level (high, low, or medium) is cumulonimbus at?

Nataly_w [17]

Cumulonimbus clouds are at a high level in the sky

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3 years ago

An electric fan is running on HIGH. After fan has been running for 1.1 minutes, the LOW button is pushed. The fan slows down to

madam [21]

Answer:

ωi = 15.4 rev/sec

Explanation:

Since the movement of the fan is rotating, we are thus dealing with Rotational motion. In rotational motion, for angular speed to take place also means angular acceleration is also occurring.

angular acceleration = α = (change in speed)/(change in time)

angular acceleration = α = Δw/Δt = (ω - ωi) /(t- t₀) ..........(equation 1)

α = (ω -ωi) /(t- 0)

α = (ω-ωi) /t

ωi = ω - αt ......................................(equation 2)

where ωi is the initial angular speed.

We replace the values for ω, t and α

ωi = 105 rad/sec - ( 4.4 rad/sec² )(1.85s) = 96.86 rad/s = 15.415747788 rev/sec

7 0

2 years ago

A 30-cm long string, with one end clamped and the other free to move transversely, is vibrating in its second harmonic. The wave

Ann [662]

Answer:

$\lambda$ = 40 cm

Explanation:

given data

string length = 30 cm

solution

we take here equation of length that is

L = $n \times \frac{1}{4} \lambda$ ...............1

total length will be here

$L = \frac{\lambda}{2} + \frac{\lambda}{4}\\$

$L = \frac{3 \lambda }{4}$

so $\lambda$ will be

$\lambda = \frac{4L}{3}\\\lambda = \frac{4\times 30}{3}$

$\lambda$ = 40 cm

5 0

3 years ago

What force must be used to do 224 Joules of work on an object over a distance of 32 meters?

cestrela7 [59]

7.625 Newtons

work = force× distance
Newtons is an accepted value for force

so take the total 224 joules and decide by distance 32 meters to find force in Newtons

4 0

3 years ago

(a) What is the entropy change of a 14.6 g ice cube that melts completely in a bucket of water whose temperature is just above t

Alex73 [517]

Answer:

a) 17.81 J/K

b) 33.325 J/K

Explanation:

The expression to use here is the following:

ΔS = Q/T

Where:

Q: heat released or absorbed

T: Temperature in K

Now, in order to do this, we need to gather the data. We know that the temperature in part a) is above the freezing temperature of water, which is 0 ° C or 273 K. and the mass of the ice cube is 14.6 g.

a) Using the water heat of fusion (Cause it's melting), we can calculated the heat released using the following expression:

Q = m * Lf

Lf = 333,000 J/kg

Solving for Q first we have:

Q = (14.6 / 1000) * 333,000

Q = 4,861.8 J

Now, the entropy change is:

ΔS = 4,861.8 / 273

ΔS = 17.81 J/K

b) In this part, we follow the same procedure than in part a) but using the water heat of boiling (Lv = 2,256,000 J/kg), the temperature of boiling which is 100 °C (or 373 K) and the mass of 5.51 g (0.00551 kg)

Calculating the heat:

Q = 0.00551 * 2,256,000 = 12,430.56 J

Now the entropy change:

ΔS = 12,430.56 / 373

ΔS = 33.325 J/K

8 0

3 years ago