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miss Akunina [59]
3 years ago
12

HELP PLZ ASAP!!

Physics
1 answer:
Andre45 [30]3 years ago
5 0
1. The successful launch of communication satellites

2.More people will be interested in studying science

But science would probably be focused on space exploration and there will probably be less scientists in other fields such as chemistry.
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[BWS.02]If the same experiment is repeated in different parts of the world by different scientists,
guajiro [1.7K]

Answer:

the results will be the same.it may be

7 0
3 years ago
A gun has a muzzle speed of 80 meters per second. What angle of elevation should be used to hit an object 180 meters away? Negle
olga55 [171]
Knowing the initial velocity and angle, the horizontal range formula is given by   R= V^2sin(2teta) / g, so we can get 
sin(2teta)=Rg/V^2
sin(2teta)= (180 x 9.8)/ 80^2= 0.27, sin(2teta)=0.27, 2teta=arcsin(0.27)=15.66, so teta=15.66/2

teta=7.83°
5 0
3 years ago
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Select all THREE of the correct response about the diagram of an atom.
STALIN [3.7K]

Answer: HI

Explanation:

Hi

5 0
2 years ago
What is the flow rate of water in a pipe flowing full with an area of 0.3 m2 and velocity of 2.5 m/s?
sashaice [31]

Answer:

0.75 m³/s

Explanation:

Applying,

Q = vA.................... Equation 1

Where Q = flow rate of the water, v = velocity of the water, A = area of the pipe.

From the question,

Given: v = 2.5 m/s, A = 0.3 m²

Substitute these values into equation 1

Q = 2.5(0.3)

Q = 0.75 m³/s

Hence the flow rate of water in the pipe is 0.75 m³/s

4 0
2 years ago
A frictionless piston–cylinder device contains 7 kg of nitrogen at 100 kPa and 250 K. Nitrogen is now compressed slowly accordin
lora16 [44]

Answer: -1038.8 kJ

Explanation:

From the question, we can see that PV^n = constant. And as such, we can deduce that it is a polytropic process. Thus, we can use the polytropic work equation to calculate the needed work input.

from the question we were given

Mass of nitrogen, m = 7kg

initial temperature, T1 = 250k

Final temperature, T2 = 450k

Polytropic index, n = 1.4

Specific gas constant, R = 0.2968kJ/kgK

W = [p2 * v2 - p1 * v1] / 1 - n

W = [m * R * T2 - T1] / 1 - n

W = 7*0.2968*(450 - 250)] / 1 - 1.4

W = [7*0.2968*200] / -0.4

W = 415.52 / -0.4

W = -1038.8 kJ

5 0
3 years ago
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