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2 years ago

A search will start from a visual lead true false

Engineering

2 answers:

taurus [48]2 years ago

5 0

True i believe is the correct answer

BlackZzzverrR [31]2 years ago

4 0

True

An organized searching process will need to start from the visual lead area. Eye focus and eye movements from the path of travel in an organized pattern describes a visual search process.

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Hi all any one help me??

yanalaym [24]

Answer:

Explanation:

sorry i dont know

5 0

3 years ago

Read 2 more answers

Calculate the current in the 8-W resistor of Figure below by using Thevenin’s theorem. What will be its value of connections of

kvv77 [185]

solution from c hegg. hope it helps. see photos explanation

7 0

4 years ago

A person has driven a car 180 m in 40 seconds. What is the car’s speed?

777dan777 [17]

Answer:

4.5 m/s = 16.2 km/h

Explanation:

The speed is the ratio of distance to time:

speed = (180 m)/(40 s) = 4.5 m/s

4 0

3 years ago

The pressure in a water line is 1500 kPa. What is the line pressure in (a) lb/ft2units and (b) lbf/in2(psi) units?

n200080 [17]

Answer:

Part A:

$1500\ KPa= 31328.145 \frac{lb}{ft^2}$

Part B:

$1500 KPa=217.55656 \frac{lb}{in^2}$ (Psi)

Explanation:

Part A:

Line Pressure is 1500 KPa

We need a conversion factor which converts KPa to lb/ft^2.

$20.88543 \frac{lb}{ft^2}= 1\ KPa$

In order to convert 1500 KPa to lb/ft^2, we proceed as:

$1\ KPa=20.88543 \frac{lb}{ft^2} \\1500\ KPa= 1500 KPa*20.88543 \frac{lb}{ft^2.KPa}\\1500\ KPa= 31328.145 \frac{lb}{ft^2}$

1500 KPa is 31328.145 lb/ft^2

Part B:

We will use the same procedure we did in Part A:

1 ft= 12 in

$(1\ ft)^2=(12\ in)^2\\1 ft^2=144 in^2$

Converting $1500 KPa\ into\ \frac{lb}{in^2}$

$1500\ KPa= 1500 KPa*20.88543 \frac{lb}{ft^2.KPa} * \frac{ft^2}{144\ in^2}$

$1500 KPa=217.55656 \frac{lb}{in^2}$ (Psi)

1500 KPa is 217.55656 lb/in^2 (psi)

3 0

3 years ago

The files provided in the code editor to the right contain syntax and/or logic errors. In each case, determine and fix the probl

Yanka [14]

Question Continuation

public class DebugOne3{

public static void main(String args){

System.out.print1n("Over the river");

System.out.pr1ntln("and through the woods");

system.out.println("to Grandmother's house we go");

}

Answer:

Line 2: Invalid Syntax for the main method. The main method takes the form

public static void main (String [] args) { }

public static void main (String args []) { }

Line 3: The syntax to print is wrong.

To print on a new line, make use of System.out.println(".."); not System.out.print1n();

Line 4:

To print on a new line, make use of System.out.println(".."); not System.out.pr1ntln();

Line 5:

The case of "system" is wrong.

The correct case is sentence case, "System.out.println" without the quotes

The correct program goes, this:

public class DebugOne3{

public static void main(String [] args){

System.out.println("Over the river");

System.out.println("and through the woods");

System.out.println("to Grandmother's house we go");

}

Explanation:

3 0

3 years ago