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2 years ago

A search will start from a visual lead true false

Engineering

2 answers:

taurus [48]2 years ago

5 0

True i believe is the correct answer

BlackZzzverrR [31]2 years ago

4 0

True

An organized searching process will need to start from the visual lead area. Eye focus and eye movements from the path of travel in an organized pattern describes a visual search process.

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In a production turning operation, the foreman has decreed that a single pass must be completed on the cylindrical workpiece in

stellarik [79]

Answer:

V = 125.7m/min

Explanation:

Given:

L = 400 mm ≈ 0.4m

D = 150 mm ≈ 0.15m

T = 5 minutes

F = 0.30mm ≈ 0.0003m

To calculate the cutting speed, let's use the formula :

$T = \frac{pi* D * L}{V*F}$

We are to find the speed, V. Let's make it the subject.

$V = \frac{pi* D * L}{F*T}$

Substituting values we have:

$V = \frac{pi* 0.4 * 0.15}{0.0003*5}$

V = 125.68 m/min ≈ 125.7 m/min

Therefore, V = 125.7m/min

7 0

3 years ago

Kinetic energy is defined as energy of an object in:

Murrr4er [49]

your answer is c. motion

5 0

3 years ago

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Need help solving math problem using integration

notka56 [123]

Ummm did you try to add or subtract and multiply or divide that can get your answer

8 0

2 years ago

You guys are amazing :D

Sloan [31]

Ik i am thank you tho xoxo

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3 years ago

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A single-cylinder pump feeds a boiler through a delivery

Studentka2010 [4]

Answer:

Net discharge per hour will be 3.5325 $m^3/hr$

Explanation:

We have given internal diameter d = 25 mm

Time = 1 hour = 3600 sec

So radius $r=\frac{d}{2}=\frac{25}{2}=12.5mm=12.5\times 10^{-3}m$

We know that area is given by

$A=\pi r^2=3.14\times (12.5\times 10^{-3})^2=490.625\times 10^{-6}m^2$

We know that discharge is given by $Q=AV$ , here A is area and V is velocity

So $Q=AV=490.625\times 10^{-6}\times 2=981.25\times 10^{-6}m^3/sec$

So net discharge in 1 hour = $981.25\times 10^{-6}m^3/sec\times 3600=3.5325m^3/hour$

8 0

3 years ago