Answer:
A.) Find the answer in the explanation
B.) Ua = 7.33 m/s , Vb = 7.73 m/s
C.) Impulse = 17.6 Ns
D.) 49%
Explanation:
Let Ua = initial velocity of the rod A
Ub = initial velocity of the rod B
Va = final velocity of the rod A
Vb = final velocity of the rod B
Ma = mass of rod A
Mb = mass of rod B
Given that
Ma = 2kg
Mb = 1kg
Ub = 3 m/s
Va = 0
e = restitution coefficient = 0.65
The general expression for the velocities of the two rods after impact will be achieved by considering the conservation of linear momentum.
Please find the attached files for the solution
Com·ma
/ˈkämə/
NOUN
1. a punctuation mark (,) indicating a pause between parts of a sentence. It is also used to separate items in a list and to mark the place of thousands in a large numeral.
2. a minute interval or difference of pitch.
Answer:
import java.util.*;
public class Main {
public static void main(String[] args) {
double milesPerGallon = 0;
int totalMiles = 0;
int totalGallons = 0;
double totalMPG = 0;
Scanner input = new Scanner(System.in);
while(true){
System.out.print("Enter the miles driven: ");
int miles = input.nextInt();
if(miles <= 0)
break;
else{
System.out.print("Enter the gallons used: ");
int gallons = input.nextInt();
totalMiles += miles;
totalGallons += gallons;
milesPerGallon = (double) miles/gallons;
totalMPG = (double) totalMiles / totalGallons;
System.out.printf("Miles per gallon for this trip is: %.1f\n", milesPerGallon);
System.out.printf("Total miles per gallon is: %.1f\n", totalMPG);
}
}
}
}
Explanation:
Initialize the variables
Create a while loop that iterates until the specified condition is met inside the loop
Inside the loop, ask the user to enter the miles. If the miles is less than or equal to 0, stop the loop. Otherwise, for each trip do the following: Ask the user to enter the gallons. Add the miles and gallons to totalMiles and totalGallons respectively. Calculate the milesPerGallon (divide miles by gallons). Calculate the totalMPG (divide totalMiles by totalGallons). Print the miles per gallon and total miles per gallon.
Answer:
heat transfer rate is -15.71 kW
Explanation:
given data
Initial pressure = 4 bar
Final pressure = 12 bar
volumetric flow rate = 4 m³ / min
work input to the compressor = 60 kJ per kg
solution
we use here super hated table for 4 bar and 20 degree temperature and 12 bar and 80 degree is
h1 = 262.96 kJ/kg
v1 = 0.05397 m³/kg
h2 = 310.24 kJ/kg
and here mass balance equation will be
m1 = m2
and mass flow equation is express as
m1 = 
.......................1
m1 = 
m1 = 1.2353 kg/s
and here energy balance equation is express as
0 = Qcv - Wcv + m × [ ( h1-h2) + 
+ g (z1-z2) ] ....................2
so here Qcv will be
Qcv = m × [ 
] ......................3
put here value and we get
Qcv = 1.2353 × [ {-60}+ (310.24-262.96) ]
Qcv = -15.7130 kW
so here heat transfer rate is -15.71 kW
