3LiOH+Fe(NO3)3--›Fe(OH)3↓+3LiNO3
n(LiOH)=m/M=(25g)/(24g/mol)=1,0417mol
n(Fe(OH)3)=1/3n(LiOH)=0,3472mol
m(Fe(OH)3)=n*M=0,3472mol*107g/mol=37,15g
Answer:
<u>only sodium chloride compounds</u> MOST LIKELY products of the reaction between sodium metal and chlorine gas.
Correct answer - C
Explanation:
A solid sodium metal reacts with gaseous form of chlorine gas to form a solid sodium chloride.
This formation of sodium chloride arises due to transfer of one valence electron from sodium to chlorine atom and the both atoms get stable octet electronic configuration.
As a result, an ionic compound solid sodium chloride is formed.
The chemical reaction of formation sodium chloride is as follows.

Therefore, <u>only sodium chloride compounds</u> MOST LIKELY products of the reaction between sodium metal and chlorine gas.
<h3>answer:</h3><h3>es un cambio fisico</h3>
Explanation:
It is known that the maximum value of ml is equal to the vale of l. But the minimum value of n is as follows.
n = l + 1
where, n = principle quantum number
l = azimuthal quantum number
Values of n can be 1, 2, 3, 4 and so on. Whereas the values of l is 0 for s, 1 for p, 2 for d, 3 for f, and so on.
Also, "m" is known as magnetic quantum number whose values can be equal to -l and +l.
- Electronic configuration of Li is
. So here, n = 2, l = 0, m = 0 and s = ±
.
- Electronic configuration of
is
. So here, n = 4, l = 1, m = -1, 0, +1, and s = ±
.
- Electronic configuration of
is
. So here, n = 5, l = 1, m = -1, 0, +1, and s = ±
.
- Electronic configuration of B is
. So here, n = 2, l = 1, m = -1, 0, +1, and s = ±
.