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Rufina [12.5K]
3 years ago
9

What is the charge on a magnesium ion? How do they get that charge?

Chemistry
2 answers:
jeyben [28]3 years ago
6 0

Answer:

Explanation:  Magnesium ion has the charge of units +2. Magnesium belongs to the group of Alkaline earth metals which have 2 valence electrons in their outermost shell.

Thus when the valence electrons are lost  for the formation of the new chemical bond, then the metal atom will get the charge equal to the lost electrons as the number of positively charged ions increases in comparison to the negatively charged ions.

This leads to the creation of the positive charge on the Magnesium ion.

seropon [69]3 years ago
4 0
A) Magnesium is in group 2. That means it has two electrons in its outer shell when these are lost, a magnesium ion is formed Mg2+ is formed. 

b) A magnesium ion get its charge because it has the two electrons in the outer electron shell of a magnesium shell. Both are lost when it changes to an ion leaving it with 12 positively charged protons and 10 negatively charged electrons. This produces a +2 positive charge.
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What is kinetic energy of a 155 kg object moving at speed of 20 m/s
Novay_Z [31]

Answer:

KE = 1/2*m*v^2

KE = 1/2*150kg*(20 m/s)^2

KE = 75kg * 400m²/s²

KE = 30,000 kg*m²/s²

KE = 30,000 N*m

KE = 30,000 J

Explanation:

Hope this helped.

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4 0
2 years ago
A 0.216 g sample of carbon dioxide, CO2, has a volume of 507 mL and a pressure of 470 mmHg. What is the temperature of the gas i
Gala2k [10]

Answer:

The temperature of the gas is 876.69 Kelvin

Explanation:

Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:  

P*V = n*R*T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas.

In this case:

  • P= 470 mmHg
  • V= 570 mL= 0.570 L
  • n= 0.216 g= 0.0049 moles (being the molar mass of carbon dioxide is 44 g/mole)
  • R= 62.36367 \frac{mmHg*L}{mol*K}
  • T=?

Replacing:

470 mmHg*0.570 L= 0.0049 moles* 62.36367 \frac{mmHg*L}{mol*K} *T

Solving:

T=\frac{470 mmHg*0.570 L}{0.0049 moles* 62.36367\frac{mmHg*L}{mol*K} }

T= 876.69 K

<em><u>The temperature of the gas is 876.69 Kelvin</u></em>

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