Answer:
In West Africa, garri refers to the creamy granular flour obtained by processing the starchy tuberous roots of freshly harvested cassava. ... Flour foodstuffs mixed with cold or boiled water are a major part of the diet amongst the various ethnicities of Nigeria, Benin Republic, Togo, Ghana, Guinea, Cameroon and Liberia.
Explanation:
Answer:
The acronym CHNOPS, which stands for carbon, hydrogen, nitrogen, oxygen, phosphorus, sulfur, represents the six most important chemical elements whose covalent combinations make up most biological molecules on Earth. All of these elements are nonmetals.
Answer:
T2 = 133.333°K
Explanation:
Using Combined Gas Laws:
(600 torr)(10L)/500°K = (200 torr)(8L)/x°K

Cross multiply:
x°K (600 torr)(10L) = 500°K(200 torr)(8L)
Divide:
x°K = (500°K(200 torr)(8L))/(600 torr)(10L)

x = 400/3°K or 133.333°K
Hey there!
theoretical yield = (87* 100 ) / 60 = 145 g of phosphorous pentachloride
the reaction for this process is :
molar mass P2O5 => 239.2125 g/mol
molar mass P4 => 123.90 g/mol
molar mass Cl2 => 70.9060 g/mol
P4 + 5 Cl2 --------------> 2 P2Cl5
moles of P2O5 :
145 g / 239.2125 => 0.6062 moles of P2O5
Therefore:
moles of P4 = 0.6062 mol / 2 => 0.3031 moles
moles of Cl2 = 5/2 * 0.6062 mol = 1.5154 moles
mass of P4 ( phosphours ) = 0.3031 mol * 123.90 => 37.554 grams
mass of Cl2 ( chlorine ) = 1.5154 mol * 70.9060 => 107.45 grams
Hope That helps!
Explanation:
Let us assume that the ratio for the given reaction is 1:1.
Therefore, we will calculate the moles of
as follows.
Moles of
solution = molarity × volume (L)
= 0.0440 M × 0.014 L
= 0.000616 moles
Moles of excess EDTA = 0.000616 moles
Also, the initial moles of EDTA will be calculated as follows.
Total initial moles of EDTA = 0.0600 M × 0.025 L
= 0.0015
Therefore, moles of EDTA reacted with
will be as follows.
= 0.0015 - 0.000616
= 0.00088 moles
Since, we have supposed a 1 : 1 ratio between
and EDTA
.
So, moles of
= 0.00088 moles
Now, we will calculate the molarity of
as follows.
Molarity of
solution =
=
= 0.015 M
Thus, we can conclude that the original concentration of the
solution is 0.015 M.