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4 years ago

Please help on this one

Physics

1 answer:

Sphinxa [80]4 years ago

6 0

Since this is a projectile motion problem, break down each of the five kinematic quantities into x and y components. To find the range, we need to identify the x component of the displacement of the ball.

Let's break them down into components.

X Y

v₁ 32 cos50 m/s 32 sin50 m/s

v₂ 32 cos50 m/s ?

Δd ? 0

Δt ? ?

a 0 -9.8 m/s²

Let's use the following equation of uniform motion for the Y components to solve for time, which we can then use for the X components to find the range.

Δdy = v₁yΔt + 0.5ay(Δt)²

0 = v₁yΔt + 0.5ay(Δt)²

0 = Δt(v₁ + 0.5ayΔt), Δt ≠ 0

0 = v₁ + 0.5ayΔt

0 = 32sin50m/s + 0.5(-9.8m/s²)Δt

0 = 24.513 m/s - 4.9m/s²Δt

-24.513m/s = -4.9m/s²Δt

-24.513m/s ÷ 4.9m/s² = Δt

5.00s = Δt

Now lets put our known values into the same kinematic equation, but this time for the x components to solve for range.

Δdₓ = v₁ₓΔt + 0.5(a)(Δt)²

Δdₓ = 32cos50m/s(5.00s) + 0.5(0)(5.00)²

Δdₓ = 32cos50m/s(5.00s)

Δdₓ = 102.846

Therefore, the answer is A, 102.9m. According to significant digit rules, neither would be correct, but 103m is the closest to 102.9m so I guess that is what it is.

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