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Lubov Fominskaja [6]
3 years ago
6

Determine how many hydrogen atoms a compound has if it is a hydrocarbon and it’s carbon atom skeleton is C=C-C=C.

Physics
2 answers:
Len [333]3 years ago
5 0

Refer to the attachment

  • Total 6 hydrogens

DochEvi [55]3 years ago
4 0

Answer: If you have such a carbon skeleton, then the formula is

H

−

C

≡

C

−

C

H

3

, propyne,

C

3

H

4

.

Explanation:

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A penny is dropped from the top of a building 290 m high. Ignoring air resistance, if
mel-nik [20]

Answer:

Vf = 75.4 m/s

Explanation:

In order to find the final velocity of the penny when it would hit the ground, we will use the equation of motion. In this particular case the third equation of motion can be used. The third equation of motion is written as follows:

2gh = Vf² - Vi²

where,

Vf = Final Velocity of the penny when it would hit the ground = ?

Vi = Initial Velocity of the penny = 0 m/s (Since, the penny starts from rest)

g = acceleration due to gravity = 9.8 m/s²

h = height of building = 290 m

Therefore,

2(9.8 m/s²)(290 m) = Vf² - (0 m/s)²

Vf = √(5684 m²/s²)

<u>Vf = 75.4 m/s</u>

3 0
3 years ago
Nicholas spends 20 minutes ironing shirts with his 1,800-watt iron. How many joules of energy were used
ivanzaharov [21]
Multiply the power (1,800 watts) by time (1,200 seconds) to get 2,160,000 joules (or 2.16 MJ)
7 0
3 years ago
3. Two spherical objects at the same altitude move with identical velocities and experience the same drag force at a time t. If
Daniel [21]

Answer:

Object 2 has the larger drag coefficient

Explanation:

The drag force, D, is given by the equation:

D = 0.5 c \rho A v^2

Object 1 has twice the diameter of object 2.

If d_2 = d

d_1 = 2d

Area of object 2, A_2 = \frac{\pi d^2 }{4}

Area of object 1:

A_1 = \frac{\pi (2d)^2 }{4}\\A_1 = \pi d^2

Since all other parameters are still the same except the drag coefficient:

For object 1:

D = 0.5 c_1 \rho A_1 v^2\\D = 0.5 c_1 \rho (\pi d^2) v^2

For object 2:

D = 0.5 c_2 \rho A_2 v^2\\D = 0.5 c_2 \rho (\pi d^2/4) v^2

Since the drag force for the two objects are the same:

0.5 c_1 \rho (\pi d^2) v^2 = 0.5 c_2 \rho (\pi d^2/4) v^2\\4c_1 = c_2

Obviously from the equation above, c₂ is larger than c₁, this means that object 2 has the larger drag coefficient

8 0
3 years ago
Will binoculars work properly if their prisms (assume n = 1.50) are immersed in water (nwater= 1.33)? assume that binoculars wor
Amanda [17]

The binoculars will not work properly.

Please refer to the diagram attached.

Binoculars work on the principle of total internal reflection. The incident ray from air enters the prism through on face normally and it strikes the opposite face at an angle of 45°. The ray undergoes Total internal reflection if its critical angle is less than the angle of incidence,which , in this case is 45°.

The critical anglei_{c} is related to the refractive index of the material of glass μ as shown below.

\mu =\frac{1}{sini_c}

For a refractive index equal to 1.5, the critical angle is found as shown below.

sini_c=\frac{1}{\mu} \\ =\frac{1}{1.5} \\ =0.666

Take the inverse of the value 0.666 to determine the critical angle.

sin^{-1} (0.666)=41.8^o

The critical angle in air is less than the angle of incidence, and hence total internal reflection occurs in air.

When the binoculars are immersed in water, the ray passes into the glass through water. therefore, the refractive index of the prism when immersed in water is given by,

\mu_g_w=\frac{\mu_g}{\mu_w}

Therefore the critical angle <em>c</em> in this case is given by,

sinc=\frac{\mu_w}{\mu_g}

Substitute 1.33 for \mu_w and 1.5 for \mu_g.

sinc=\frac{\mu_w}{\mu_g} \\ =\frac{1.33}{1.5} \\ =0.8866

Take the inverse of the value 0.8866.

c=sin^{-1} (0.8866)\\ =62^o

Since the critical angle of the prism when immersed in water, is 62°, which is greater than the angle of incidence of 45° required for viewing the object, the binoculars which are set for Total reflection in air, will not function when immersed in water.

4 0
4 years ago
When water (H₂O) freezes into ice, some of the properties have changed. What stays the same?
erastova [34]

Answer:

1st one

identity of the H₂O

When water (H2O) freezes into ice, some of the properties have changed but the identity of the H2O is the same. Explanation; Water can exist in liquid, solid; ice and gaseous state; steam. Freezing occurs when water is continuously cool until it turns to solid ice, water freezes at zero degree Celsius

Hope This Helps

4 0
2 years ago
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