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Art [367]
3 years ago
5

Does peer pressure affect your physical activity routine? Describe this peer pressure and tell whether it is positive or negativ

e.
Physics
2 answers:
Alexxx [7]3 years ago
4 0
Yes, peer pressure affects one's physical activity routine. It can do so both negatively and positively. For instance, if one is pressured to do drugs when around their peers, it would most likely lead to an addiction that lasts even when they are not with those people anymore. However, from a positive viewpoint, one's peers could also pressure them to do something productive, such as trying a new beneficial activity that they are afraid of (ex. trying out for a talent show.) This could lead to a disruption in routine as that individual would begin practicing for said talent show. Hence, peer pressure can be both negative and positive, but in both instances, it changes the routine of the individual effected. 
Serga [27]3 years ago
3 0

Yes, peer pressure does affect your physical activity routine. Peer pressure can do both negative and positive. A negative way of peer pressure is having an addiction to drugs after these people have been leaned into drugs they will now do them even when the people that gave it to them are not around. A positive way of peer pressure is someone pressuring you to do something positive like to start working out. This would end up to you to start a workout routine.  

Hope it helps :)

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A closed-end organ pipe is used to produce a mixture of sounds. The third and fifth harmonics in the mixture have frequencies of
nexus9112 [7]

Answer:

F_1=366.67Hz

Explanation:

From the question we are told that:

Frequency of 3rd harmonics F_3=1100

Frequency of 5th harmonics F_3=1833

Generally the equation for Wavelength at 3rd Harmonics is mathematically given by

 \lambda_3=\frac{4}{3}l

Therefore

 F_3=\frac{3v}{4l}

Generally the equation for Wavelength at 1st Harmonics is mathematically given by

 \lambda_1=\frac{4}{1}l

Therefore

 F_1=\frac{v}{4l}

Generally the equation for the frequency of the first harmonic is mathematically given by

 F_1=\frac{F_3}{3}

 F_1=\frac{1100}{3}

 F_1=366.67Hz

7 0
3 years ago
How many wavelengths are seen in this image of a sound wave?<br><br> three<br> four<br> six<br> ten
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Four water levels are shown
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3 years ago
Read 2 more answers
Why is Pluto considered less of an oddball planet now?
solmaris [256]

Answer:

The International Astronomical Union (IAU) downgraded the status of Pluto to that of a dwarf planet because it did not meet the three criteria the IAU uses to define a full-sized planet. Essentially Pluto meets all the criteria except one—it “has not cleared its neighboring region of other objects

Explanation:

4 0
2 years ago
A solid block, with a mass of 0.15kg, on a frictionless surface is pushed directly onto a horizontal spring, with a spring const
iren [92.7K]

Answer:

16.1 m/s

Explanation:

We can solve the problem by using the law of conservation of energy.

At the beginning, the spring is compressed by x = 35 cm = 0.35 m, and it stores an elastic potential energy given by

U=\frac{1}{2}kx^2

where k = 316 N/m is the spring constant. Once the block is released, the spring returns to its natural length and all its elastic potential energy is converted into kinetic energy of the block (which starts moving). This kinetic energy is equal to

K=\frac{1}{2}mv^2

where m = 0.15 kg is the mass of the block and v is its speed.

Since the energy must be conserved, we can equate the initial elastic energy of the spring to the final kinetic energy of the block, and from the equation we obtain we can find the speed of the block:

\frac{1}{2}kx^2=\frac{1}{2}mv^2\\v=\sqrt{\frac{kx^2}{m}}=\sqrt{\frac{(316 N/m)(0.35 m)^2}{0.15 kg}}=16.1 m/s

4 0
3 years ago
A vehicle of mass 1600kg take off from rest and coveres a distance of 280m in 60s. It continues at this speed for 98seconds and
Lady bird [3.3K]
1. V = Vo + a*t. 
<span>15 = 0 + a*5 a = 3 m/s^2. </span>

<span>2. V = Vo + a*t. </span>
<span>0 = 15 - 5*t, t = 3 s. </span>

<span>3. d1 = Vo*t + 0.5a*t^2. </span>
<span>Vo = 0, t = 5, a = 3 m/s^2, d1 = ?. </span>

<span>d2 = Vo*t. Vo = 15 m/s, t = 15 s, </span>
<span>d2 = ?. </span>

<span>V^2 = Vo^2 + 2a*d3. </span>
<span>V = 0, Vo = 15 m/s, a = -5 m/s^2, d3 = ?. </span>

<span>d1+d2+d3 = Total dist.</span>
4 0
3 years ago
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