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2 years ago

How does light of different frequency react when they pass through a prism (material with higher refractive index)?

Physics

1 answer:

GalinKa [24]2 years ago

7 0

Answer:

I believe the answer is that the light with the higher frequency refracts more than light with a lower frequency

Explanation:

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a 1020-hertz sound wave travels at 340 m/s in air with a wavelength of a) 30 m. b) 3 m. c) 0.333 m. d) 1 m. e) none of the above

eimsori [14]

The wavelength of the sound wave is equal to 0.333 m. Therefore, option (c) is correct.

<h3>What are frequency and wavelength?</h3>

The frequency of the wave can be defined as the number of oscillations that occur in one second and can be expressed in hertz. The wavelength can be defined as the distance between the two adjacent points of a wave such as two crests or troughs.

The relationship between frequency (ν), speed of sound waves (V), and wavelength (λ):

V = νλ

Given, the frequency of the sound wave, ν = 10 Hz

The speed of the sound wave, $V = 340 m/s$

The wavelength of the sound waves can determine as follows

λ = V/ν = 340/1020 = 0.333 m.

Therefore, the wavelength of the sound wave is 0.333 m

Learn more about wavelength and frequency, here:

brainly.com/question/18651058

#SPJ1

5 0

1 year ago

Can someone please help me come up with a hypothesis?. The question that I have is "How many sugars are in your smoothies?"

patriot [66]

'I believe that there is 20 grams of sugar in the smoothies.'

I don't know, just an idea.

8 0

3 years ago

Read 2 more answers

The coefficient of linear expansion of copper is 17 x 10^-6 K-1. A block of copper 30 cm wide, 45 cm long, and 10 cm thick is he

schepotkina [342]

Answer:

The change in volume is $6.885\times 10^{- 5}\$

Solution:

As per the question:

Coefficient of linear expansion of Copper, $\alpha = 17\times 10^{- 6}\ K^{- 1}$

Initial Temperature, T = $0^{\circ}$ = 273 K

Final Temperature, T' = $100^{\circ}$ = 273 + 100 = 373 K

Now,

Initial Volume of the block, V = $30\times 45\times 10\times 10^{- 6}\ m^{3} = 0.0135\ m^{3}$

$V' = V(1 + \gamma \Delta T)$

$\gamma = 3\alpha$

$V' = V(1 + 3\alpha \Delta T)$

where

V' = Final volume

$V' - V= 0.0135\times 17\times 10^{- 6} \times (T' - T))$

$\Delta V= 0.0135\times 3\times 17\times 10^{- 6} \times (373 - 273)) = 6.885\times 10^{- 5}\$

7 0

3 years ago

Simple physics (Final) (Pic provided)

Igoryamba

Answer:

15m/s

Explanation:

Divide distance by time

3 0

3 years ago

If the speed of sound in air is 343 m/s and the wavelength of this note is 2.62 m, what is the frequency of this C3 note? (Round

snow_lady [41]

Answer:

The frequency of of the note = 131 Hz.

Explanation:

Frequency: Frequency can be defined as the number of complete oscillation completed by a wave in one seconds. The S.I unit of frequency is Hertz ( Hz)

v = λf ............................ Equation 1

Making f the subject of the equation,

f = v/λ .......................... Equation 2

Where v = Speed, λ = wavelength, f = frequency

Given: v = 343 m/s, λ = 2.62 m.

Substituting these values into equation 2

f = 343/2.62

f = 131 Hz

Thus the frequency of of the note = 131 Hz.

8 0

3 years ago