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2 years ago

What happens if you dont have any bones? would you be able to live?

Physics

2 answers:

attashe74 [19]2 years ago

7 0

Answer: no

Explanation: Our skeleton is a very rigid structure of bones that provides support for our muscles, skin and its task is also to protect our vital organs. Without the bone, we would be unable to do anything, because our nerves, blood flow, lungs, organs would be blocked and squeezed.

lyudmila [28]2 years ago

6 0

Answer:

Explanation:

Without bones, we would have no structural frame for our skeleton, we would be unable to move our skeleton, which would leave our internal organs poorly protected, cause lack blood and be short on calcium.

Hope this helps!

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A flywheel with a diameter of 1.63 m is rotating at an angular speed of 79.9 rev/min. (a) What is the angular speed of the flywh

Studentka2010 [4]

Answer:

(a) 8.362 rad/sec

(b) 6.815 m/sec

(d) 396.22 revolution

Explanation:

We have given that diameter d = 1.63 m

So radius $r=\frac{d}{2}=\frac{1.63}{2}=0.815m$

Angular speed N = 79.9 rev/min

(a) We know that angular speed in radian per sec

$\omega =\frac{2\pi N}{60}=\frac{2\times 3.14\times 79.9}{60}=8.362rad/sec$

(b) We know that linear speed is given by

$v=r\omega =0.815\times 8.362=6.815m/sec$

And $\omega _i=79.9rev/min$

Time t = 63 sec

Angular acceleration is given by $\alpha =\frac{\omega _f-\omega _i}{t}=\frac{675-79.9}{63}=9.446rad/sec^2$

(d) Change in angle is given by

$\Theta =\frac{1}{2}(\omega _i+\omega _f)t=\frac{1}{2}(675+79.9)\times 1.05=396.22rev$

7 0

2 years ago

A 7950-kg railroad car travels alone on a level frictionless track with a constant speed of 15.0 m/s . A 2950-kg load, initially

Alchen [17]

The new speed of car is 10.9 m/s

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According to the principle of momentum conservation, momentum is only modified by the action of forces as they are outlined by Newton's equations of motion; momentum is never created nor destroyed inside a problem domain.

Mass of the railroad car, m₁ = 7950 kg

Mass of the load, m₂ = 2950 kg

It can be assumed as the speed of the car, u₁ = 15 m/s

Initially, it is at rest, u₂ = 0

Let v is the speed of the car. It can be calculated using the conservation of momentum as :

$m_1u_1 + m_2u_2 = (m_1 + m_2) v$

$v =\frac{m_1u_1}{m_1+m_2}$

$v = \frac{7950*15}{7950+2950}$

$v= 10.9 m/s$

Therefore, the new speed of care is 10.9 m/s

Learn more about momentum here:

brainly.com/question/22257327

#SPJ1

5 0

1 year ago

Den pushes a desk 400 cm across the floor. He exerts a force of 10 N for 8 s to move the desk.

stellarik [79]

Answer: The correct option is Option b.

Explanation:

Power is defined as the rate of work done by an object.

Mathematically,

$P=\frac{W}{t}$ .....(1)

And work done is the product of force exerted on the object times the displacement covered by that object.

Mathematically,

$W=F.s$

Putting this value in above equation, we get:

$P=\frac{F.s}{t}$

where,

P = power = ?W

F = Force exerted = 10N

s = Displacement = 400cm = 4m (Conversion factor: 1m = 100 cm)

t = Time taken = 8s

Putting values in above equation, we get

$P=\frac{10\times 4}{8}\\\\P=5W$

Hence, the correct option is Option b.

7 0

3 years ago

Read 2 more answers

You are given a parallel plate capacitor that has plates of area 29 cm2 which are separated by 0.0100 mm of nylon (dielectric co

GalinKa [24]

Answer:

20.60 kV

Explanation:

Capacitance of parallel plates without dielectric between them is:

$C=\frac{\varepsilon_{0}A}{d}$

with d the distance between the plates, A the area of the plates and ε₀ the constant $8.85419\times10^{-12}\frac{C^{2}}{Nm^{2}}$ , so :

$C_0=\frac{(8.85419\times10^{-12})(0.0029)}{0.0100\times10^{-3}}=2.57\times10^{-9} F$

But the dielectric constant is defined as:

$k=\frac{C}{C_{0}}$

With C the effective capacitance (with the dielectric) and Co the original capacitance (without the dielectric). So, the new capacitance is:

$C=kC_0$

But capacitance is related with voltage by:

$C=\frac{Q}{V}$

with Q the charge and V the voltage, using the new capacitance and solving for V:

$kC_0=\frac{Q}{V}$

$V=\frac{Q}{kC_0}=\frac{0.18\times10{-3}}{(3.4)(2.57\times10^{-9})}=20599.68V=20.60 kV$

4 0

2 years ago

Read 2 more answers

a car traveling at 24 m/s starts to decelerate steadily. It comes to a complete stop in 6 seconds what is its acceleration?

Irina18 [472]

We can solve for the acceleration by using a kinematic equation. First we should identify what we know so we can choose the correct equation.

We are given an original velocity of 24 m/s, a final velocity of 0 m/s, and a time of 6 s. We and looking for acceleration (a) in m/s^2.

The following equation has everything we need:

$v_f=v_i + at$

So plug in the known values and solve for a:

0 = 24 + 6a

-24 = 6a

a = -4 m/s^2

8 0

3 years ago