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natka813 [3]
2 years ago
11

What is an athlete’s momentum if the athlete has a velocity of 7.5 m/s and has a mass of 70kg?

Physics
1 answer:
Bezzdna [24]2 years ago
8 0

Answer:

525 kg.m/s

Explanation:

★ Momentum = Mass× Velocity

→ P = (7.5 × 70) kg.m/s

→ P = (75 × 7) kg.m/s

→ <u>P</u><u> </u><u>=</u><u> </u><u>5</u><u>2</u><u>5</u><u> </u><u>kg</u><u>.</u><u>m</u><u>/</u><u>s</u>

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Gibbons, small Asian apes, move by brachiation, swinging below a handhold to move forward to the next handhold. A 9.0 kg gibbon
aleksklad [387]

Answer:

230 N

Explanation:

At the lowest position , the velocity is maximum hence at this point, maximum support force  T  is given by the branch.

The swinging motion of the ape on a vertical circular path , will require

a centripetal force  in upward direction . This is related to weight as follows

T - mg = m v² / R

R is radius of circular path . m is mass of the ape and velocity is 3.2 m/s

T =  mg -  mv² / R

T = 8.5 X 9.8 + 8.5 X 3.2² / .60  { R is length of hand of ape. }

T = 83.3 + 145.06

= 228.36

= 230 N ( approximately )

5 0
3 years ago
If the half life of an isotope is 20 years, how much of the original amount will
Feliz [49]

Answer:

Half

Explanation:

6 0
3 years ago
Read 2 more answers
A book is sitting on a table. Which of the following is true about the table? O A. It is pushing up on the book. O B. It exerts
777dan777 [17]

Answer:

yes it does exert a force, it pushes it up

Explanation:

this is called normal force

if it didn't exert a force the book would keep going down

according to newton every force has an equal amd opposite reaction

so the book exerts a force on the table and vice versa

hope this helped

5 0
2 years ago
Trace fossils would include all of the following EXCEPT
Vadim26 [7]

Answer:

Im pretty sure its fossilized nests because nests arent tracings. hope this helps

Explanation:

6 0
3 years ago
A block with mass 0.470 kg sits at rest on a light but not long vertical spring that has spring constant 85.0 N/m and one end on
a_sh-v [17]

Answer: elastic potential energy = 20.27 J

Explanation:

Given that the

Mass M = 0.470 kg

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But according to conservative of energy, the maximum kinetic energy is equal to the maximum potential energy experienced by the block of mass M.

That is

K .E = P.E = mgh

Where g = 9.8m/s^2

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K.E = 20.27 J

Where K.E = maximum elastic potential energy stored in the spring during the motion of the blocks after the collision which is 20.27J.

4 0
3 years ago
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