Answer:
Part A
Kp = 3.4 x 10⁴
Part B
Kp = 2.4 x 10⁻¹⁴
Part C
Kp = 1.2 x 10⁹
Explanation:
2PH₃(g) + As₂(g) ⇌ 2 AsH₃(g) + P₂(g) Kp = 2.9 x 10⁻⁵
Kp = [AsH₃]²[P₂]/[PH₃]²[As] = 2.9 x 10⁻⁵
Part A
it is the inverse of the equilibrium given
Kp(A) = 1/ Kp = 1 / 2.9 x 10⁻⁵ = 3.4 x 10⁴
Part B
Is the equilibrium where the coefficients have been multiplied by 3,
Kp(B) = ( Kp )³ = ( 2.9 x 10⁻⁵ )³ = 2.4 x 10⁻¹⁴
Part C
This is the reverse equilibrium multipled by 2.
Kp(C) = ( 1/Kp)² = ( 1/ 2.9 x 10⁻⁵ )² = 1.2 x 10⁹
If it is a true or false questions, the answer is TRUE.
Answer:
(3) 34.5grammes of C2H6O
(4) 5.56 x 10^22 Formula units
(5) 0.5 moles of CaCO3
Explanation:
(3) molar mass of C2H6O = 24 + 6 + 16 = 46 g/mol
mass of C2H6O =0.75 mole x 46 g/mole = 34.5 grammes
(4) Formula units of NaCl = (5.4/ 58.5) x 6.022x10^23 = 5.56 x 10^22
(4) moles = mass / molar mass
molar mass of CaCO3 = 40 + 12 + 48 = 100 g/mol
moles of CaCO3 = 50/100 = 0.5 moles
4 sig fig in that expression
<span>pH= 3.744 + log [HCO2-]/[HCO2H] </span>
