Question

A beam of microwaves with λ = 0.9 mm is incident upon a 9 cm slit. At a distance of 1.5 m from the slit, what is the approximate width of the slit's image (cm)?

Answer 1

Answer:

3 cm

Explanation:

According to the question,

$D=1.5 m$.

$d=9 cm$.

$\lambda =0.9 mm$.

Now the approximate slit's image width is equal to width of central maxima.

And width of central maxima is twice the width from center to first maxima

So,

$y=2\frac{\lambda (D)}{d}$.

Substitute all the variable in above equation.

$y=\frac{(2)0.9\times 10^{-2} m(1.5 m) }{0.09 m}$.

$y=3 cm$.