Answer:
Explanation:
initial height = 0.5*gt^2 = 0.5*9.8*1.5 = 7.35 m
now,
<em>x - x0 = ut + 1/2at^2
</em>
<em>
</em>
<em>0 - 7.35 = 50sin(30)*t + (1/2)*(-9.8)*t^2
</em>
<em>
</em>
<em>4.9t^2 - 25t - 7.35 = 0
</em>
solving this and taking only the positive value of t
t = (sqrt(76906)+250)/98 or <em>5.3808 secs</em>
a)
s = 50*cos(30 degree)*(sqrt(76906)+250)/98
<h2><u>
s = 232.9959 m or 234 approx.</u></h2>
Answer:
yes.
Explanation:
Suppose height of 32 ft is reached after t seconds . Putting the values in the given equation gives real value of t that means it reaches the height of 32 feet
So 32 = 16 + 32t-16t²
16t²- 32t+16 = 0
t² - 2t + 1 = 0
t = 1 s
So real value of t is obtained . That means it reaches the height of 32 ft.
Answer:
Part a)
Part b)
Direction = upwards
Explanation:
When ball is dropped from height h = 4.0 m
then the speed of the ball just before it will strike the ground is given as
Now ball will rebound to height h = 2.00 m
so the velocity of ball just after it will rebound is given as
Part a)
Average acceleration is given as
Part B)
As we know that ball rebounds upwards after collision while before collision it is moving downwards
So the direction of the acceleration is vertically upwards
Answer:
E=1/2kmv^2
Explanation:
To get the formula...
The dimension of energy is [ M^1 L^2 T^-2]
The dimension of mass [M]=[M^1 L ^0T ^0]
Dimension of velocity[V]=[M ^0 L ^1 T ^−1]
Let [E]=k[M] ^x[V] ^y
K is constant and it remain a dimensionless quantity.
Therefore, M ^1L ^2T ^−2]=k[M ^1L ^0T ^0] x[M ^0L ^1 T ^−1] y
So, x=1,y=2
E= Kmv^2
K=1/2
Therefore E is 1/2kmv^2.
Answer:
The same number of atoms of each element must appear on both sides of a chemical equation. However, simply writing down the chemical formulas of reactants and products does not always result in equal numbers of atoms. You have to balance the equation to make the number of atoms equal on each side of an equation.
Explanation:
I hope thats what u needed.
