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2 years ago

Why hands are not heated by conduction when placed on a vertical placed copper sheet

Physics

1 answer:

Mademuasel [1]2 years ago

8 0

Answer:

A conduction heating material with a cylindrical shape and a 5 cm radius is being heated in high temperature (85 C) air from an initial temperature of 10 C

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The earth’s orbit around the sun is elliptical. What does this word mean?.

omeli [17]

Answer:

An elliptical orbit is the revolving of one object around another in an oval-shaped path called an ellipse. The planets in the solar system orbit the sun in elliptical orbits. Many satellites orbit the Earth in elliptical orbits as does the moon.

3 0

1 year ago

What is the kinetic energy of an object that has a mass of 50.0 kg and a velocity of 18 m/s? A.450 J B.900 J C.8,100 J D.16,000

Svet_ta [14]

KE = (1/2)·(mass)·(speed)²

KE = (1/2)·(50 kg)·(18 m/s)²

KE = (25 kg)·(324 m²/s²)

KE = 8,100 kg-m²/s²

KE = 8,100 Joules

5 0

3 years ago

Read 2 more answers

1600 AM broadcasts radio waves with wavelengths<br> of about 187.37 m. Convert this to miles.

nikklg [1K]

Answer:

The wavelength in miles is <u>0.1165 miles</u>.

Explanation:

Given:

Wavelength of the radio wave is 187.37 m.

Now, the wavelength is given in meters.

We need to convert the wavelength from meters to miles.

In order to convert meters to miles, we have to use their conversion factor.

We know that,

1 meter = $\frac{1}{1609}\ miles$

Therefore, the conversion factor is given as:

$CF=\frac{1}{1609}\ miles\ per\ meter$

So, the wavelength in miles is given as:

$Wavelength=\textrm{Wavelength in meters}\times CF\\\\Wavelength=187.37\ m\times \frac{\frac{1}{1609}\ miles}{1\ m}\\\\Wavelength=\frac{187.37}{1609}\ miles\\\\Wavelength=0.1165\ miles$

Hence, the wavelength in miles is 0.1165 miles.

7 0

3 years ago

a chuck wagon with an initial velocity of 4 m/s and a mass of 35 kg gets a push with 350 joules of force. what is the wagon's fi

Kitty [74]

Answer:

the final velocity of the wagon is 6 m/s.

Explanation:

Given;

initial velocity of the wagon, u = 4 m/s

mass of the wagon, m = 35 kg

energy applied to the wagon, E = 350 J

The final velocity of the wagon is calculated as;

E = ¹/₂m(v² - u²)

$m(v^2-u^2) = 2E\\\\v^2-u^2 = \frac{2E}{m} \\\\v^2 = \frac{2E}{m} + u^2\\\\v = \sqrt{\frac{2E}{m} + u^2} \\\\v = \sqrt{\frac{2(350)}{35} + (4)^2}\\\\v = 6 \ m/s$

Therefore, the final velocity of the wagon is 6 m/s.

8 0

2 years ago

A charge of 19 nC is uniformly distributed along a straight rod of length 15 m that is bent into a circular arc with a radius of

Salsk061 [2.6K]

Answer:

The magnitude of the electric field at the center of curvature of the arc is 3.87 N/C

Explanation:

Please see the attachments below

8 0

3 years ago