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LiRa [457]
2 years ago
6

X^2-10x+29 in the form (x-a)^2+b​

Mathematics
1 answer:
Ymorist [56]2 years ago
5 0

Answer:

x^2-10x+29=(x-5)^2+4

Step-by-step explanation:

x^2-10x+29\\\\x^2-10x+25+4\\\\(x-5)^2+4

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The length of a rectangle is 2 feet less than twice the width. The area of the rectangle is 180 feet squared. Find the length an
Ksenya-84 [330]

Answer:

Width=10

Length=18

Step-by-step explanation:

The length is 2 feet less then twice the width

Let the width be x.

Then the length is 2x -2 based on the given information. Use this to make an equation since it is known that the area is 180feet squared.

x(2x-2)=180

2x^2 - 2x - 180 = 0

2( x^2 - x - 90) = 0

We now have a factorable quadratic.

2(x+9)(x-10)=0

So by zero product property, x=-9, x=10 Since a measure cannot be negative, -9 is an extraneous solution.

So x=10

Then the width is 10 and the length is 18

Hope this helps! Let me know if it is correct!

3 0
3 years ago
5. The recursive algorithm given below can be used to compute gcd(a, b) where a and b are non-negative integer, not both zero.
s2008m [1.1K]

Implementating the given algorithm in python 3, the greatest common divisors of <em>(</em><em>124</em><em> </em><em>and</em><em> </em><em>244</em><em>)</em><em> </em>and <em>(</em><em>4424</em><em> </em><em>and</em><em> </em><em>2111</em><em>)</em><em> </em>are 4 and 1 respectively.

The program implementation is given below and the output of the sample run is attached.

def gcd(a, b):

<em>#initialize</em><em> </em><em>a</em><em> </em><em>function</em><em> </em><em>named</em><em> </em><em>gcd</em><em> </em><em>which</em><em> </em><em>takes</em><em> </em><em>in</em><em> </em><em>two</em><em> </em><em>parameters</em><em> </em>

if a>b:

<em>#checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>is</em><em> </em><em>greater</em><em> </em><em>than</em><em> </em><em>b</em>

return gcd (b, a)

<em>#if</em><em> </em><em>true</em><em> </em><em>interchange</em><em> </em><em>the</em><em> </em><em>Parameters</em><em> </em><em>and</em><em> </em><em>Recall</em><em> </em><em>the</em><em> </em><em>function</em><em> </em>

elif a == 0:

return b

elif a == 1:

return 1

elif((a%2 == 0)and(b%2==0)):

<em>#even</em><em> </em><em>numbers</em><em> </em><em>leave</em><em> </em><em>no</em><em> </em><em>remainder</em><em> </em><em>when</em><em> </em><em>divided</em><em> </em><em>by</em><em> </em><em>2</em><em>,</em><em> </em><em>checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>and</em><em> </em><em>b</em><em> </em><em>are</em><em> </em><em>even</em><em> </em>

return 2 * gcd(a/2, b/2)

elif((a%2 !=0) and (b%2==0)):

<em>#checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>is</em><em> </em><em>odd</em><em> </em><em>and</em><em> </em><em>B</em><em> </em><em>is</em><em> </em><em>even</em><em> </em>

return gcd(a, b/2)

else :

return gcd(a, b-a)

<em>#since</em><em> </em><em>it's</em><em> </em><em>a</em><em> </em><em>recursive</em><em> </em><em>function</em><em>,</em><em> </em><em>it</em><em> </em><em>recalls</em><em> </em><em>the function</em><em> </em><em>with </em><em>new</em><em> </em><em>parameters</em><em> </em><em>until</em><em> </em><em>a</em><em> </em><em>certain</em><em> </em><em>condition</em><em> </em><em>is</em><em> </em><em>satisfied</em><em> </em>

print(gcd(124, 244))

print()

<em>#leaves</em><em> </em><em>a</em><em> </em><em>space</em><em> </em><em>after</em><em> </em><em>the</em><em> </em><em>first</em><em> </em><em>output</em><em> </em>

print(gcd(4424, 2111))

Learn more :brainly.com/question/25506437

6 0
3 years ago
If 16 key chains cost cost $19.68 how much do 25 key chains cost
Vsevolod [243]
We know how much 16 keychains is, now we need to find how much one is.

19.68 / 16 = $1.23

$1.23 is the price of one keychain, now you can multiply that by 25 to see how much 25 keychains cost.
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3 years ago
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Esme plans to flip a fair coin 3 times and record the results of each flip.
Feliz [49]

Answer:

⅛

Step-by-step explanation:

P(H&H&H) = ½ × ½ × ½ = ⅛

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