2 years ago

A high-quality sleeping bag will keep you warm even during a winter camping trip

Chemistry

1 answer:

vagabundo [1.1K]2 years ago

4 0

Answer:

Bundling up, starting a fire, body warmth, blankets, taking a hot shower/bath.

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Identify the parts of the telescope.

Alona [7]

Eyepiece, finder-scope, optical tube, aperture, focuser, and mount

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3 years ago

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3. How many moles are in 1.49 x 1023 molecules of iodine?

tino4ka555 [31]

Answer:

<h3>The answer is 0.25 moles</h3>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

$n = \frac{1.49 \times {10}^{23} }{6.02 \times {10}^{23} } = \frac{1.49}{6.02} \\ = 0.247508305...$

We have the final answer as

<h3>0.25 moles</h3>

Hope this helps you

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3 years ago

The atom below with the greatest number of valence electrons is _______. A. Cl: 1S2 2S2 2P6 3S2 3P5 B. Br: 1S2 2S2 2P6 3S2 3P6 4

allochka39001 [22]

Me. It has 6 valence electrons. Everything else has 5

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4 years ago

5. A 5.00 g sample of an unknown substance was heated from 25.2 C to 55.1 degrees * C , and it required 133 to do so. Identify t

Leviafan [203]

Answer:

Aluminum

Explanation:

Given

$T_1 = 25.2^oC$

$T_2 = 55.1^oC$

$m = 5.00g$

$\triangle Q= 133J$

<em>See attachment for chart</em>

Required

Identify the unknown substance

To do this, we simply calculate the specific heat capacity from the given parameters using:

$c = \frac{\triangle Q}{m\triangle T}$

This gives:

$c = \frac{\triangle Q}{m(T_2 - T_1)}$

So, we have:

$c = \frac{133J}{5.00g * (55.1C - 25.2C)}$

$c = \frac{133J}{5.00g * 29.9C}$

$c = \frac{133J}{149.5gC}$

$c = 0.89\ J/gC$

From the attached chart, we have:

$Al(s) = 0.89\ J/gC$ --- The specific heat capacity of Aluminum

<em>Hence, the unknown substance is Aluminum</em>

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3 years ago

_____ Na3PO4 + _____ KOH arrow _____ NaOH + ___________K3PO4 <br> How do I balance this equation?

soldi70 [24.7K]

The answer is na3po4+3koh=3naoh+k3po4

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3 years ago