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ANTONII [103]
2 years ago
11

A high-quality sleeping bag will keep you warm even during a winter camping trip

Chemistry
1 answer:
vagabundo [1.1K]2 years ago
4 0

Answer:

Bundling up, starting a fire, body warmth, blankets, taking a hot shower/bath.

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Xà phòng hoá hoàn toàn 22,2g hỗn hợp gồm 2 este HCOOC2h5 và ch3cooch3 bằng dung dịch naoh 1m ( đun nóng) thể tích dung dịch naoh
lisabon 2012 [21]

Answer:

I can't understand your language? can you write in English

I'm sorry

4 0
3 years ago
The ability of an atom in a molecule to attract electrons is best quantified by the ________.
nevsk [136]

Answer:

b. electronegativity

Explanation:

The ability of an atom in a molecule to attract electrons is best quantified by the _Electronegativity_.

Electronegativity is the ability of an atom to attract a shared pair of electron which is loosely held. Polar molecules often possess such properties. The Halogen group (group 17) is famous for such property because it has the highest electronegativity in periodic table.  

7 0
3 years ago
What is 8S8 <br><br> In need for a quick answer
kirza4 [7]

Answer:

8x8 Inc. is a provider of Voice over IP products. 8x8 products include cloud-based voice, contact center, video, mobile and unified communications for businesses.

Explanation:

7 0
3 years ago
with the help of balanced chemical equation explain what happens when zinc is put in dilute hydrochloric acid
blagie [28]
They react to form salt  ZnCl + hydrogen gas

3 0
3 years ago
Two samples of the same compound are compared. what does the data represent? sample 1: 24.22 g carbon and 32.00 g oxygen sample
goblinko [34]

According to law of definite proportion:

In a compound, elements are always arranged in fixed ratio by mass.

Here, sample 1 has 23.22 g Carbon and 32.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

n_{C}=\frac{m_{C}}{M_{C}}=\frac{24.22 g}{12 g/mol}\approx 2 mol

Similarly, number of moles of oxygen will be:

n_{O}=\frac{m_{O}}{M_{O}}=\frac{32 g}{16 g/mol}=2 mol

The ratio of number of moles of carbon and oxygen will be:

C:O=n_{C}:n_{O}=2:2=1:1

Therefore, formula of compound will be CO.

Sample 2:

It has 36.22 g Carbon and 48.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

n_{C}=\frac{m_{C}}{M_{C}}=\frac{36.22 g}{12 g/mol}\approx 3 mol

Similarly, number of moles of oxygen will be:

n_{O}=\frac{m_{O}}{M_{O}}=\frac{48 g}{16 g/mol}=3 mol

The ratio of number of moles of carbon and oxygen will be:

C:O=n_{C}:n_{O}=3:3=1:1

The formula of compound will be CO.

Therefore, it is proved that carbon and oxygen are present in fixed ratios in both the samples.


4 0
3 years ago
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