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schepotkina [342]
2 years ago
7

If you evaporated 125 mL of a 3.5 M solution of iron(II) nitrite, how many moles of iron(II) nitrite would you recover?

Chemistry
1 answer:
Verizon [17]2 years ago
3 0

Considering the definition of molarity, 0.4375 moles of iron(II) nitrite you would recover.

In order to find the moles of the solid that can be recovered from this solution, you need to use the definition of molarity.

<h3>Definition of molarity</h3>

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

Molarity=\frac{number of moles}{volume}

Molarity is expressed in units \frac{moles}{liters}.

Moles of iron(II) nitrite

In this case, you evaporated 125 mL of a 3.5 M solution of iron(II) nitrite​. Then you know:

  • Molarity= 3.5 M
  • number of moles= ?
  • volume= 125 mL= 0.125 L (being 1000 mL= 1 L)

Replacing in the definition of molarity:

3.5 M=\frac{number of moles}{0.125 L}

Solving:

number of moles= 3.5 M× 0.125 L

<u><em>number of moles= 0.4375 moles</em></u>

Finally, 0.4375 moles of iron(II) nitrite you would recover.

Learn more about molarity:

brainly.com/question/9324116

brainly.com/question/10608366

brainly.com/question/7429224

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How many moles of NH3 would be formed from the complete reaction of 16.0 g H2?
natima [27]

Taking into account the reaction stoichiometry, 5.33 moles of NH₃ are formed from the complete reaction of 16 grams of H₂.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

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<h3>Mass of NH₃ formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 6 grams of H₂ form 2 moles of NH₃, 16 grams of H₂ form how many moles of NH₃?

moles of NH_{3}= \frac{16 grams of H_{2} x2moles of NH_{3}}{6 grams of H_{2}}

<u><em>moles of NH₃= 5.33 moles</em></u>

Then, 5.33 moles of NH₃ are formed from the complete reaction of 16 grams of H₂.

Learn more about the reaction stoichiometry:

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