If you evaporated 125 mL of a 3.5 M solution of iron(II) nitrite, how many moles of iron(II) nitrite would you recover?
1 answer:
Considering the definition of molarity, 0.4375 moles of iron(II) nitrite you would recover.
In order to find the moles of the solid that can be recovered from this solution, you need to use the definition of molarity.
<h3>Definition of molarity</h3>Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.
The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:
Molarity is expressed in units .
Moles of iron(II) nitrite
In this case, you evaporated 125 mL of a 3.5 M solution of iron(II) nitrite. Then you know:
- Molarity= 3.5 M
- number of moles= ?
- volume= 125 mL= 0.125 L (being 1000 mL= 1 L)
Replacing in the definition of molarity:
Solving:
number of moles= 3.5 M× 0.125 L
<u><em>number of moles= 0.4375 moles</em></u>
Finally, 0.4375 moles of iron(II) nitrite you would recover.
Learn more about molarity:
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3.47 x atoms of gold have mass of 113.44 grams.
Explanation:
Data given:
number of atoms of gold = 3.47 x
mass of the gold in given number of atoms = ?
atomic mass of gold =196.96 grams/mole
Avagadro's number = 6.022 X
from the relation,
1 mole of element contains 6.022 x atoms.
so no of moles of gold given =
0.57 moles of gold.
from the relation:
number of moles =
rearranging the equation,
mass = number of moles x atomic mass
mass = 0.57 x 196.96
mass = 113.44 grams
thus, 3.47 x atoms of gold have mass of 113.44 grams