Observation of experiment and intervention in newton's optics. newton followed the principle of light through prisms and the rays transmitted through them as a part of his observation. Various properties of light and its characteristics were exposed.
Explanation:
- Newton's investigation of light was based on prisms, lenses and optical rays.
- He stated that lights differing in colour also differed in degrees of re-frangibility.
- To support his theories newton employed "Proof by experiments" method. Each method was designated in revealing a specific property of light.
- A phenomenon known as Newton rings were discovered by newton.
- Newton recognized after pressing together two prisms that there was a transparent spot.
<span>a. They produce ions when dissolved in water.
acids in water
</span>
<span>HA + H2O --> H3O+ + A-</span>
HA --> H+ + A<span>-</span>
bases
B + H2O --> OH - + BH+
Answer:
Jeweler B = more accurate
Jeweler A = more precise
Error:
0.008, 0
% error :
0.934% ; 0
Explanation:
Given that:
True mass of nugget = 0.856
Jeweler A: 0.863 g, 0.869 g, 0.859 g
Jeweler B: 0.875 g, 0.834 g, 0.858 g
Official measurement (A) = 0.863 + 0.869 + 0.859 = 2.591 / 3 = 0.864
Official measurement (B) = 0.875 + 0.834 + 0.858 = 2.567 / 3 = 0.8556
Accuracy = closeness of a measurement to the true value
Accuracy = true value - official measurement
Jeweler A's accuracy :
0.856 - 0.864 = - 0.008
Jeweler B's accuracy :
0.856 - 0.856 = 0.00
Therefore, Jeweler B's official measurement is more accurate as it is more close to the true value of the gold nugget.
However, Jeweler A's official measurement is more precise as each Jeweler A's measurement are closer to one another than Jeweler B's measurement which are more spread out.
Error:
Jeweler A's error :
0.864 - 0.856 = 0.008
% error =( error / true value) × 100
% error = (0.008/0.856) × 100% = 0.934%
Jeweler B's error :
0.856 - 0.856 = 0 ( since the official measurement as been rounded to match the decimal representation of the true value)
% error = 0%
1.0566 gal.
H O W E V E R
the constant formula you can use for solving and simplifying equations such as these, you can simply look up the metric system online and figure one out. hoped this helped!
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