All categories

2 years ago

BRAINLIEST OF CORRECT Match the atom to the number of electrons it is likely to gain/lose,

Physics

2 answers:

beks73 [17]2 years ago

6 0

The atoms according to the number of electrons it will lose or gain is matched as follows;

Sodium → lose 1

Nitrogen → gain 3

Sulphur → gain 2

Fluorine → gain 1

Boron → lose 3

Beryllium → lose 2

<h3>Atoms</h3>

Atoms are the building block of matter. The outermost electron of an atom determines the number of electron an atom loose during bonding. Therefore,

Na(sodium) with an outermost electron of one will lose 1 electron to attain the octet rule.
Nitrogen with an outermost electron of 5 will easily gain 3 electrons to attain the octet rule
Sulphur(S) with an outermost electron of 6 will easily gain 2 electrons to attain the octet rule
Fluorine with an outermost electron of 7 will easily gain 1 electrons to attain the octet rule
Boron with an outermost electron of 3 will easily loose 3 electrons to attain the octet rule
Beryllium with an outermost electron of 2 will easily loose 2 electrons to attain the octet rule

learn more on electrons here:brainly.com/question/5141076

jenyasd209 [6]2 years ago

5 0

Answer:

Na: lose 1

O: gain 2

Al: lose 3

Be: lose 2

N: gain 3

Cl: depends on the limit of your study im grade nine and the energy level M can hold only eight electrons so i would have answered (gain 1)

Explanation:

You might be interested in

what voltage would produce a current of 100A through an aluminum wire that has a resistance of 3.44x10^-4 ohm?

Serga [27]

Voltage = Current x Resistance
Voltage(?) = 100 x 1.98x10^-4 ohms 

Voltage = Current x Resistance 
Voltage(?) = 250 x 2.09x10^-4 ohms 

Voltage = Current x Resistance 
Voltage(?) = 100 x 3.44x10^-4 ohms

7 0

2 years ago

In nuclear reaction 5 kg of reactants give 2kg of products

dlinn [17]

Choice A is correct.======Kinetic energy equation: KE = (1/2)(m)(v²)This tells us that KE is directly proportional to mass and the square of velocity. In other words, the more mass and more velocity an object has, the more kinetic energy.If an object is sitting at the top of a ramp, there is no velocity and therefore no kinetic energy. Choices B and D are wrong.A golf ball has more mass than a ping-pong ball, so a ping-pong ball would have less kinetic energy than a golf ball rolling off the end of a ramp. Choice C is wrong.Choice A is correct.

6 0

2 years ago

A hungry rat is placed in a maze. It walks the following path to find a piece of cheese. 4.0m N, 7.5 m E, 6.8 m S, 3.7 m E, 3.6

storchak [24]

Answer:

Explanation:

We shall take the help of vector form of displacement . Taking east as i and north as j

4.0m N = 4 j

7.5 m E = 7.5 i

6.8 m S = - 6.8 j

3.7 m E, = 3.7 i

3.6 m S = - 3.6 j

5.3 m W = - 5.3 i

3.7 m N, = 3.7 j

5.6 m W = - 5.6 i

4.4 m S = - 4.4 j

4.9 m W = - 4.9 i

Total displacement = 4j +7.5 i -6.8j+3.7i-3.6j-5.3i+3.7j-5.6i-4.4j-4.9i

= -4.6 i -7.1 j

magnitude of displacement = $\sqrt{(4.6^2+7.1^2)}$

= 8.46 m

Direction

Tanθ = 7.1/ 4.6

θ = 57⁰ south of west .

distance walked = 4+7.5 +6.8+3.7+3.6+5.3+3.7+5.6+4.4+4.9

= 49.5 m

6 0

3 years ago

Read 2 more answers

What is the weight of an object (mass = 60 kilograms) on Mars, where the acceleration due to gravity is 3.75 meters/second2?. Se

Shalnov [3]

Weight = mass * gravity = 60 kg * 3.75 m/s² = 225 N

Option D.

7 0

3 years ago

A block weighing 400 kg rests on a horizontal surface and supports on top of it ,another block of weight 100 kg which is attache

Paladinen [302]

Answer:

$F_a=1470\ N$

Explanation:

Friction Force

When objects are in contact with other objects or rough surfaces, the friction forces appear when we try to move them with respect to each other. The friction forces always have a direction opposite to the intended motion, i.e. if the object is pushed to the right, the friction force is exerted to the left.

There are two blocks, one of 400 kg on a horizontal surface and other of 100 kg on top of it tied to a vertical wall by a string. If we try to push the first block, it will not move freely, because two friction forces appear: one exerted by the surface and the other exerted by the contact between both blocks. Let's call them Fr1 and Fr2 respectively. The block 2 is attached to the wall by a string, so it won't simply move with the block 1.

Please find the free body diagrams in the figure provided below.

The equilibrium condition for the mass 1 is

$\displaystyle F_a-F_{r1}-F_{r2}=m.a=0$

The mass m1 is being pushed by the force Fa so that slipping with the mass m2 barely occurs, thus the system is not moving, and a=0. Solving for Fa

$\displaystyle F_a=F_{r1}+F_{r2}.....[1]$

The mass 2 is tried to be pushed to the right by the friction force Fr2 between them, but the string keeps it fixed in position with the tension T. The equation in the horizontal axis is

$\displaystyle F_{r2}-T=0$