Answer
given,
copper rod length = 50 cm
density of the copper = 8.92 g/cm³
iron rod length = 50 cm
density of iron = 7.86 g/cm³
mass of iron = density × volume
m_i = 7.86 × A × l/2
m_c = 8.96 × A × l/2
taking the intersection of copper and iron rod be starting point cooper side is taken as positive side and iron side length is taken to be -ve side.
center of mass
=
=
=
=
= 0.015793 m
= 1.579 m (+ve)
center of mass shift to cooper because cooper is heavy.
Answer:
(A) The magnitude of the tension increases to four times its original value, 4F.
Explanation:
When an object moves in circular motion, a centripetal force acts on it . In this scenario the centripetal force acting on the stone is given by .
Where m is the mass of object
v- velocity or speed of the object
r - radius of the circle
Important to note is that the tension is equal to the centripetal force.
Given that initially the string makes one complete revolution per second and then speeds up to make two complete revolutions in a second .It implies that the speed has doubled .
Using our equation :F =
where F is the tension in the string
let the initial speed be =v then after it doubles it becomes 2v
Keeping the radius of the circle unchanged we have :
F=
From the equation it can be seen that the initial Tension has increased by a factor of 4 .
Therefore the magnitude of the tension increases to four times its original value, 4F.
Considering that Work, W, is:
W=F·d
You have: 224=F·32
So that F=7 N
Answer:
Q = 5267J
Explanation:
Specific heat capacity of copper (S) = 0.377 J/g·°C.
Q = MSΔT
ΔT = T2 - T1
ΔT=49.8 - 22.3 = 27.5C
Q = change in energy = ?
M = mass of substance =508g
Q = (508g) * (0.377 J/g·°C) * (27.5C)
Q= 5266.69J
Approximately, Q = 5267J