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Annette [7]
2 years ago
11

The airplanes parts and functions​

Chemistry
1 answer:
SpyIntel [72]2 years ago
6 0

Answer: The main sections of an airplane include:

fuselage: The plane’s body, or fuselage, holds the aircraft together, with pilots sitting at the front of the fuselage, passengers and cargo in the back.

Wings: An aircraft’s wings are critical to flight through the production of lift, but they have many parts of the wing to control this lift amount and direction.

Cockpit: The cockpit is the area at the front of the fuselage from which a pilot operates the plane

Engine: The engine(s), or powerplant, of an aircraft creates thrust needed for the plane to fly.

Propeller: An aircraft’s propeller(s) are airfoils, similar to a wing, installed vertically to create thrust to drive the plane forward.

Tail assembly: An aircraft’s tail is mainly used for stability, as well as creating lift in combination with the wings. It’s comprised of several parts.

Landing gear: Landing gear is located under the belly of the plane consisting of a wheel and strut to soften impact with the ground and may be retractable into the fuselage.

Explanation:

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A mixture of 0.600 mol of bromine and 1.600 mol of iodine is placed into a rigid 1.000-L container at 350°C.
kaheart [24]

The equilibrium constant of the reaction is 282. Option D

<h3>What is equilibrium constant?</h3>

The term equilibrium constant refers to the number that often depict how much the process is able to turn the reactants in to products. In other words, if the reactants are readily turned into products, then it follows that the equilibrium constant will be large and positive.

Concentration of bromine = 0.600 mol /1.000-L = 0.600 M

Concentration of iodine = 1.600 mol/1.000-L =  1.600M

In this case, we must set up the ICE table as shown;

              Br2(g) + I2(g) ↔ 2IBr(g)

I          0.6            1.6           0

C      -x                -x             +2x

E    0.6 - x         1.6 - x       1.190

If 2x = 1.190

x = 1.190/2

x = 0.595

The concentrations at equilibrium are;

[Br2] = 0.6 -  0.595 = 0.005

[I2] =   1.6 - 0.595 = 1.005

Hence;

Kc = [IBr]^2/[Br2] [I2]

Kc = ( 1.190)^2/(0.005) (1.005)

Kc = 282

Learn more about equilibrium constant:brainly.com/question/15118952

#SPJ1

4 0
2 years ago
What types of questions can be answered through science and what questions are beyond the boundaries of science? Be specific and
Anna [14]
The questions tha science can answer are those can be tested to try to find a definite answer.

For example, whether light is wave or particle is matter of science.

Questions that cannot have a definite answer are the field of religion or philosophy, and are out of the boundaries of science.

For example, does a criminal deserve the punishment of not seeing light? It is a moral question, which to be responded needs the intervention of philosophy and that could have different anwers at different times and in different societies.

 


3 0
3 years ago
Iron and aluminum are examples of _____________.<br><br> <br><br>​
LenKa [72]

Answer:

Iron and aluminum are examples of metals, along with copper, iron, (etc.)

6 0
3 years ago
That's just the tip of the iceberg" is a popular expression you may have heard. It means that what you can see is only a small p
puteri [66]
Answer:

B 1.23 g/cc

Explanation:
For something to float on seawater, the density must be less than 1.03 g/mL. If the object sinks, the density is greater than 1.03 g/mL.

Let’s examine the answer choices. Keep in mind, the ice berg is mostly below the water level.

A. 0.88 g/cc
This is less than 1.03 g/cc, which would result in floating.

B. 1.23 g/cc
This is the best answer choice. The iceberg is mostly beneath the water, but some of it is exposed. The density is greater than 1.03 g/mL, but not so much greater that it would immediately sink.

C. 0.23 g/cc
This is less than 1.03 g/cc, which would produce floating.

D. 4.14 g/cc
This is much greater than 1.03 g/cc and the result would be sinking.
5 0
3 years ago
A weak acid (ha) has a pka of 4.001. If a solution of this acid has a ph of 4.110, what percentage of the acid is not ionized? (
OverLord2011 [107]

99.9224 % of the acid is not ionized.

____HA + H₂O ⇌ A⁻ + H₃O⁺

I: ___<em>c</em> ________0 ____0  

C: _-α<em>c</em> _______+α<em>c</em> __+α<em>c </em>

E: <em>c</em>(1-α) _______α<em>c</em> ___α<em>c </em>

pH = 4.110

[H₃O⁺] = α<em>c</em> = 10^(-4.110) mol/L = 7.76 × 10⁻⁵ mol/L

α = 7.76 × 10⁻⁵

1 – α = 1 - 7.76 × 10⁻⁵ = 0.999 224 = 99.9224 %

7 0
3 years ago
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