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Klio2033 [76]
3 years ago
8

A scientist designs an experiment in which a light source is pointed at a substance and a light detector is placed on the opposi

te side of the substance.
When the light source is turned on, the scientist observes that no light is detected on the far side of the substance. What is the best interpretation for this observation?

A. The light was either reflected or transmitted by the substance.
B. The light was both absorbed and reflected by the substance.
C. The light was both reflected and transmitted by the substance.
D. The light was either absorbed or reflected by the substance.

Physics
2 answers:
worty [1.4K]3 years ago
6 0

Answer:

option D

Explanation:

When a light falls on a substance, it can reflect, absorb or transmitted by it. It is possible that a combination of above phenomenon occurs.

In the given situation, as no light is detected by the light detector, it means that no light is transmitted by the substance. The light must be either absorbed or bounced back (reflected).

Thus, option D is correct.

Lostsunrise [7]3 years ago
5 0
The answer is D. Either absorbed or reflected. The reason is because if no light is being shown on the other side, the substance is not letting any light pass through. Since we do not know anything else about the substance, we do not know which one of the two it is doing. The scientist would not see any light on the detector if 100% of the light is reflected and the same thing would happen if 100% of the light was absorbed.
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Answer:

The average current density at the position of the area.

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3 years ago
As a 2.0-kg object moves from (4.4 i + 5j) m to ( 11.6 i - 2j) m, the constant resultant force
aliina [53]

Answer:

v_f = 10.38 m / s

Explanation:

For this exercise we can use the relationship between work and kinetic energy

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note that the two quantities are scalars

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          W = F. Δx

the bold are vectors.  The displacement is

          Δx = r_f -r₀

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          Δx = (7.2 i - 7 j) m

 

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remember that the dot product

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           i.j = 0

           

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           Ko = ½ m vo²

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we substitute in the initial equation

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3 0
3 years ago
A scientific law:
vladimir1956 [14]
D. All of the above

This is true because scientific laws are all 3:
• They are well tested (to become a definite law)
• They are usually in equation form; for example: (e=mc^2)
• They are usually an example of a scientific model. The model generally will demonstrate the principle.

Hope this helps! ✅
3 0
3 years ago
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Answer:

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There are two types of reflection; specular and diffuse. Specular reflection occurs when light rays are reflected from a fine smooth surface, while diffuse reflection is observed when light rays are reflected in all directions due to the rough nature of the surface. Comparing the surfaces of a mirror and vase, that of a mirror is smoother than that of a vase. So there would be a specular reflection when light strikes a mirror, but a diffuse reflection when it strikes a solid yellow vase.

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