D) the just noticeable difference.
Explanation:
Just noticeable difference (jnd) is defined as how much a difference in stimuli is required to detect a difference between stimuli. This difference threshold changes is dependence of the intensity of stimulus.In this case, it will be the smallest change in volume that a person can sense.The intensity level of stimuli plays a role in how much you can notice change.For example in a room with very, very dim light where lights are off, a small change in light intensity produced by a ringing phone can be detected quicker by people in that room than when the lights are on and the phone rings.
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Absolute Threshold https://brainly.in/question/8377534
Keywords : sound, absolute threshold, just noticeable difference
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Phenomenon has to travel occur to the waves
The answer to question 9 is the last one, be elevator is 10m/s and the other is -10m/s as they are going in different directions so one will be negative
Answer:
Between 2.0 s and 4.0 s (B and C)
Between 5.0 s and 8.0 s (D and E)
Between 10.0 s and 11.0 s (F and G)
Explanation:
The graph shown in the figure is a velocity-time graph, which means that:
- On the x-axis, the time is plotted
- On the y-axis, the velocity is plotted
Therefore, this means that the object is not moving when the line is horizontal (because at that moment, the velocity is constant, so the object is not moving). This occurs in the following intervals:
Between 2.0 s and 4.0 s (B and C)
Between 5.0 s and 8.0 s (D and E)
Between 10.0 s and 11.0 s (F and G)
From the graph, it would be possible to infer additional information. In particular:
- The area under the graph represents the total distance covered by the object
- The slope of the graph represents the acceleration of the object
Answer:
I = 18 x 10⁻⁹ A = 18 nA
Explanation:
The current is defined as the flow of charge per unit time. Therefore,
I = q/t
where,
I = Average Current passing through nerve cell
q = Total flow of charges through nerve cell
t = time period of flow of charges
Here, in our case:
I = ?
q = (9 pC)(1 x 10⁻¹² C/1 pC) = 9 x 10⁻¹² C
t = (0.5 ms)(1 x 10⁻³ s/1 ms) = 5 x 10⁻⁴ s
Therefore,
I = (9 x 10⁻¹² C)/(5 x 10⁻⁴ s)
<u>I = 18 x 10⁻⁹ A = 18 nA</u>