Answer: Calendar
Explanation: I'm pretty sure it is calendar.
Answer:
where L is the length of the ramp
Explanation:
Let L (m) be the length of the ramp, and g = 9.81 m/s2 be the gravitational acceleration acting downward. This g vector can be split into 2 components: parallel and perpendicular to the ramp.
The parallel component would have a magnitude of

We can use the following equation of motion to find out the final velocity of the book after sliding L m:

where v m/s is the final velocity,
= 0m/s is the initial velocity when it starts from rest, a = 2.87 m/s2 is the acceleration, and
is the distance traveled:


5.4 x 1014Hz
wavelength x frequency = the speed of light
Answer:
a = 8.951 m/s²
Explanation:
given,
angle = 0.52 radians
μ_s = 0.84
μ_k = 0.48
acceleration = ?
using
F + f = m a
mg sin θ + μk mg cos θ = m a
a = g sin θ + μk g cos θ
a = 9.8 x sin 0.52 + 0.48 x 9.8 x cos 0.52
a = 4.869 + 4.082
a = 8.951 m/s²
the magnitude of acceleration is a = 8.951 m/s²