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barxatty [35]
2 years ago
7

Germanium and chlorine react according to the following chemical equation:

Chemistry
1 answer:
seropon [69]2 years ago
7 0

The mass of GeCl4 that would be formed will be 1.51 g

<h3>Stoichiometric calculations</h3>

From the balanced equation of the reaction:

Ge (s) + 2Cl2 (g) →GeCl4

The mole ratio of Ge and Cl2 is 1:2.

Mole of 1.0 g Ge: 1/72.64

                               = 0.01377 mole

Mole of 1.0 g Cl2 = 1/71

                             = 0.01408 mole

Thus, Cl2 is limiting.

Mole ratio of Cl2 and GeCl4 = 2:1

Equivalent mole of GeCl4 = 0.01408/2

                                       = 0.0070 mole

Mass of 0.0070 mole GeCl4 = 0.0070 x 214.4

                                               = 1.51 g

More on stoichiometric calculations can be found here: brainly.com/question/8062886

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Assume the volume of the crew cabin is 74,000 L. The pressure is maintained at around 1.00 atm, ideally with an 80% nitrogen and
hjlf

Answer:

The number of moles of oxygen present in the crew cabin at any given time is 615.309 moles

Explanation:

The given parameters are;

Volume of the crew cabin = 74,000 L

Pressure of the crew cabin = 1.00 atm

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Hence, volume of oxygen in the crew cabin = \frac{20}{100} \times 74,000 \, L = 14,800 \, L

From the universal gas equation, we have;

n = \frac{P \times V}{R  \times  T}

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T = Temperature = 293.15 K

R = Universal Gas Constant = 0.08205 L·atm/(mol·K)

Plugging in the values, we have;

n = \frac{1 \times 14,800 }{0.08205   \times  293.15 } = 615.309 \, moles

The number of moles of oxygen present in the crew cabin at any given time = 615.309 moles.

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