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barxatty [35]
2 years ago
7

Germanium and chlorine react according to the following chemical equation:

Chemistry
1 answer:
seropon [69]2 years ago
7 0

The mass of GeCl4 that would be formed will be 1.51 g

<h3>Stoichiometric calculations</h3>

From the balanced equation of the reaction:

Ge (s) + 2Cl2 (g) →GeCl4

The mole ratio of Ge and Cl2 is 1:2.

Mole of 1.0 g Ge: 1/72.64

                               = 0.01377 mole

Mole of 1.0 g Cl2 = 1/71

                             = 0.01408 mole

Thus, Cl2 is limiting.

Mole ratio of Cl2 and GeCl4 = 2:1

Equivalent mole of GeCl4 = 0.01408/2

                                       = 0.0070 mole

Mass of 0.0070 mole GeCl4 = 0.0070 x 214.4

                                               = 1.51 g

More on stoichiometric calculations can be found here: brainly.com/question/8062886

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Which is the balanced equation for:<br> Al2O3 + Fe – Fe3O4 + AL
Sloan [31]

Answer:

4Al203 + 9Fe -> 3Fe3O4 + 8Al

Amount of Al on reactant side: 8

Amount of Al on product side: 8

Amount of O on reactant side: 12

Amount of O on product side: 12

Amount of Fe on reactant side: 9

Amount of Fe on product side: 9

6 0
3 years ago
In trying to control fall armyworms in crops, an Agriculture extension officer applied cypermethrin which was prepared by dissol
sveta [45]

Answer:

Mole fraction for C₂₂H₁₉Cl₂NO₃ = 0.0086

Explanation:

Mole fraction remains a sort of concentration. It indicates:

moles of solute / (moles of solute + moles of solvent)

Moles of solute / Total moles.

Solute: Cypermethrin → C₂₂H₁₉Cl₂NO₃

Solvent: Water (PM = 18g/mol)

We calculate moles from solvent: 1000g /18 g/mol = 55.5 moles

We calculate PM for C₂₂H₁₉Cl₂NO₃

12g/mol . 22 + 1g/mol . 19 + 35.45 g/mol . 2+ 14g/mol + 16g/mol . 3 = 416 g/m

Moles of solute: 200 g / 416g/mol = 0.481 moles

Total moles: 0.481 + 55.5 = 55.98 moles

Mole fraction for C₂₂H₁₉Cl₂NO₃ = 0.481 moles / 55.98 moles = 0.0086

8 0
3 years ago
You are asked to prepare 500 mL 0.300 M500 mL 0.300 M acetate buffer at pH 4.904.90 using only pure acetic acid ( MW=60.05 g/mol
defon

Answer:

You will need 9,0 g of acetic acid

Explanation:

The equilibrium acetate-acetic acid is:

CH₃COOH ⇄ CH₃COO⁻ + H⁺ pka = 4,76

Using Henderson-Hasselbalch you will obtain:

pH = pka + log₁₀\frac{[A^{-}]}{[HA]}

Where HA is acetic acid and A⁻ is acetate ion

4,90 = 4,76 + log₁₀\frac{[A^{-}]}{[HA]}

1,38 = \frac{[A^{-}]}{[HA]} <em>(1)</em>

As acetate concentration is 0,300M:

0,300M = [HA] + [A⁻] <em>(2)</em>

Replacing (2) in (1):

[HA] = 0,126 M

And:

[A⁻] = 0,174 M

As you need to produce 500 mL:

0,5 L × 0,126 M = 0,063 moles of acetic acid

0,5 L × 0,174 M = 0,087 moles of acetate

To produce moles of acetate from acetic acid:

CH₃COOH + NaOH → CH₃COO⁻ + Na⁺ + H₂O

Thus, moles of acetate are equivalents to moles of NaOH and all acetates comes from acetic acid, thus:

0,087 moles of acetate + 0,063 moles of acetic acid  ≡ 0,15 moles of acetic acid ×\frac{60,05 g}{1mol} = <em>9,0 g of acetic acid</em>

<em></em>

I hope it helps!

5 0
3 years ago
In a laboratory, Carlos places one plate with grape jelly and another plate with cooked brown rice inside an ant farm. The next
olga2289 [7]

Answer:

number 1, 3, and 4 :)

Explanation:

hope you do good in edge!!

4 0
3 years ago
Iron(II) chloride is formed from the reaction between iron and copper(II) chloride. Fe + CuCl2 FeCl2 + Cu If the reactants have
sertanlavr [38]

Answer: see figure attached and explanation below.

Explanation:

1) Chemical equation (given):

Fe + CuCl₂ → Cu + FeCl₂

2) ΔHf reactants: -256 kJ/mol (given)

3) ΔHf products: - 321 kJ/mol (given)

4) ΔH reaction = ΔHf products - ΔHf reactants = - 321 kJ/mol - (- 256 kJ/mol) = - 65 kJ/mol

5) Conclusion:

i) Since ΔHf of products is less (more negative) than ΔHf of reactants, the reaction is exhotermic: the reaction released energy, which is the reason why the products content less potential energy than the reactants.

ii) Then, the energy diagram is the typical one of an exothermic reaction: the products start a certain potential energy level, the energy incrases until reaching the activation energy (the energy barrier to form the activated complex) and then energy decreases until a level below the energy of the reactants.

iii) See the attached figure with such kind of diagram showing the products at a lower level than the reactans

7 0
3 years ago
Read 2 more answers
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