Answer:
The parametric equation for the position of the particle is 
.
Explanation:
Given that,
The point is
Time t = 3
Velocity 
We need to calculate the parametric equation for the position of the particle
Using parametric equation for position
....(I)
at t = 3,
Put the value into the formula
Put the value of r₀ in equation (I)
Hence, The parametric equation for the position of the particle is .
Answer:
Explanation:
This problem is based on conservation of rotational momentum.
Moment of inertia of rod about its center
= 1/12 m l² , m is mass of the rod and l is its length .
= 1 / 12 x 4.6 x .11²
I = .004638 kg m²
The angular momentum of the bullet about the center of rod = mvr
where m is mass , v is perpendicular component of velocity of bullet and r is distance of point of impact of bullet fro center .
5 x 10⁻³ x v sin60 x .11 x .5 where v is velocity of bullet
According to law of conservation of angular momentum
5 x 10⁻³ x v sin60 x .11 x .5 = ( I + mr²)ω , where ω is angular velocity of bullet rod system and ( I + mr²) is moment of inertia of bullet rod system .
.238 x 10⁻³ v = ( .004638 + 5 x 10⁻³ x .11² x .5² ) x 12
.238 x 10⁻³ v = ( .004638 + .000015125 ) x 12
.238 x 10⁻³ v = 55.8375 x 10⁻³
.238 v = 55.8375
v = 234.6 m /s
Answer:
The group one element are called alkali because when they dissolved in water they form alkaline solutions
The cyclist is moving by uniformly accelerated motion, with an initial velocity of
and an acceleration of
.
The acceleration is given by
where
is the final velocity and
is the time between the end and the beginning of the motion, and in our case it is 1.75 s. Therefore, from this relationship we can find the final velocity:
Answer:
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