Which Model represents a lithium isotope? Use your periodic table for this one! Answer:-D

If a toy has a mass of 1 kg, it has an Earth weight of

marshall27 [118]

Answer:

The answer is 9.8 N

Explanation:

As we know that the weight of an object is the amount of gravitational force acting on the object in an upward direction if the weight is acting is the downward direction.

The formula of weight:

W = Mass x Gravitational force

W = m x g

Given data:

Mass =1 kg

g = 9.8 ms-2

W = 1kg x 9.8 ms-2 = 9.8 kgms-2 ( 1 kgms-2 = N)

SO,

W = 9.8 N

The toy has an earth weight of 9.8 N.

4 0

3 years ago

Scientists were studying three different embryos to determine their relationship to humans. The notes about each embryo are show

Sholpan [36]

Answer:

The awnser is B

Explanation:

I took the test.

0 0

3 years ago

Read 2 more answers

A flute player hears four beats per second when she compares her note to an 880 Hz tuning fork (note A). She can match the frequ

ludmilkaskok [199]

Answer:

884Hz

Explanation:

Beats is the absolute difference between two frequencies therefore

Beats = f1-f2

4=f1-880

F1=880+4

F1=884Hz

7 0

3 years ago

Compare the planets Mars and Saturn. Describe how their common characteristics are similar and Compare the planets Earth and Nep

nordsb [41]

Question no. 1. Compare the planets Mars and Saturn. Describe how their common characteristics are similar:

Answer: Our solar system is located in the outer spiral arm of the milky way galaxy. our solar system has one sun and nine revolving planets and . namely

Mercury
Venus
Earth
Mars
Jupiter
Saturn
Uranus
Neptune
Pluto (small planet usually refer as dwarf)

Each star has its on moon/moons and has its own characteristics i.e , planet must be a celestial body , must have orbit around sun, have enough mass for self gravity, big enough to have gravity that clear its path from other same size object close to its orbit around sun.

Mars is the fourth from the sun and sixth is the Saturn from the sun in our solar system.

Common in Characteristics of Mars and Saturn:

Mars and Saturn both have celestial body.
Mars and Saturn both have enough mass for the gravity to get rid of rigid body forces.
Mars and Saturn both revolve around the sun in their own orbits.
Mars is the second smallest in the solar system while Saturn is second largest in the solar system.
Mars and Saturn both have their own moons. Mars has two while Saturn has 83 moons
Mars and Neptune both do not support life.

Question no. 2. Compare the planets Earth and Neptune. Describe how are they different from each other

Answer:

Earth our home planet is the third from the sun and Neptune on the other hand is the eighth from the sun in the solar system.

Common differences between Earth and Neptune

Earth is the terrestrial planet while Neptune (Ice giant) is the Jovian planet.
Earth has no ring around it, Neptune has ring around it.
Earth is closer to the sun and Neptune is far distant from the sun.
Earth consists of rocks and metals on the other hand Neptune contain gases
Earth is smaller than the Neptune in the solar system.
Earth rotates slower and Neptune rotates faster.

4 0

3 years ago

The position of a particle moving along the x-axis depends on the time according to the equation x = ct2 - bt3, where x is in me

Sav [38]

Answer:

(a): $\rm meter/ second^2.$

(b): $\rm meter/ second^3.$

(c): $\rm 2ct-3bt^2.$

(d): $\rm 2c-6bt.$

(e): $\rm t=\dfrac{2c}{3b}.$

Explanation:

Given, the position of the particle along the x axis is

$\rm x=ct^2-bt^3.$

The units of terms $\rm ct^2$ and $\rm bt^3$ should also be same as that of x, i.e., meters.

The unit of t is seconds.

(a):

Unit of $\rm ct^2=meter$

Therefore, unit of $\rm c= meter/ second^2.$

(b):

Unit of $\rm bt^3=meter$

Therefore, unit of $\rm b= meter/ second^3.$

(c):

The velocity v and the position x of a particle are related as

$\rm v=\dfrac{dx}{dt}\\=\dfrac{d}{dx}(ct^2-bt^3)\\=2ct-3bt^2.$

(d):

The acceleration a and the velocity v of the particle is related as

$\rm a = \dfrac{dv}{dt}\\=\dfrac{d}{dt}(2ct-3bt^2)\\=2c-6bt.$

(e):

The particle attains maximum x at, let's say, $\rm t_o$ , when the following two conditions are fulfilled:

$\rm \left (\dfrac{dx}{dt}\right )_{t=t_o}=0.$
$\rm \left ( \dfrac{d^2x}{dt^2}\right )_{t=t_o}$

Applying both these conditions,

$\rm \left ( \dfrac{dx}{dt}\right )_{t=t_o}=0\\2ct_o-3bt_o^2=0\\t_o(2c-3bt_o)=0\\t_o=0\ \ \ \ \ or\ \ \ \ \ 2c=3bt_o\Rightarrow t_o = \dfrac{2c}{3b}.$