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3 years ago

How do I convert 14.8 cm into MEters?

Physics

2 answers:

stellarik [79]3 years ago

6 0

Multiply it by a fraction equal to ' 1 ', like this:

(14.8 cm) x (1 meter/100 cm) = 14.8/100 = 0.148 meter

irinina [24]3 years ago

5 0

$1 cm = 0.01 m = 1 \cdot 10^{-2} m$
We can write it in this form:
$14 cm = 0.14 m = 14 \cdot 10^{-2} m$

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If a space probe sends back info on an object traveling through space at close to the speed of light astronomers will be working

OleMash [197]

The speed of light in a vacuum is 300,000,000 m/s
That is three hundred million meters per second.
Therefore, the answer is
C) millions of meters per second

8 0

3 years ago

an ice cube is placed in the sun later there is a puddle of water later still the.puddle is gone what kind of change has occured

TiliK225 [7]

Clear question is;

An ice cube is placed in the sun. Later there is a puddle of water. Later still the puddle is gone. What kind of change has occurred?

Answer:

Physical change.

Explanation:

There are two type of changes called physical change and chemical change.

In Physical changes, there is only change in the appearance of the substance and not its chemical composition. Whereas, in Chemical changes the substance changes entirely into another substance with a new chemical formula.

Now, for the ice cube, it has melted from a solid state to a liquid state. Thus, there is only a change in appearance and not its chemical composition. Thus, it's a physical change that has occurred.

7 0

4 years ago

A 78 kg skydiver can be modeled as a rectangular "box" with dimensions 24 cm × 35 cm × 170 cm . If he falls feet first, his drag

ANTONII [103]

Answer:

The terminal speed of his is 137.68 m/s.

Explanation:

Given that,

Mass of skydiver = 78 kg

Area of box $A =24\times35=840\ cm$

Drag coefficient = 0.80

Density of air $\rho= 1.2\times kg/m^3$

We need to calculate the terminal velocity

Using formula of drag force

$F_{d} = \dfrac{1}{2}\rho v^2Ac$

Where,

$\rho$ = density of air

A = area

C= coefficient of drag

Put the value into the formula

$78\times9.8=\dfrac{1}{2}\times1.2\times v^2\times24\times10^{-2}\times35\times10^{-2}\times0.80$

$v^2=\dfrac{2\times78\times9.8}{1.2\times24\times10^{-2}\times35\times10^{-2}\times0.80}$

$v=\sqrt{\dfrac{2\times78\times9.8}{1.2\times24\times10^{-2}\times35\times10^{-2}\times0.80}}$

$v=137.68\ m/s$

Hence, The terminal speed of his is 137.68 m/s.

3 0

3 years ago

If the gauge pressure of a gas is 114 kPa, what is the absolute pressure?

Anastasy [175]

Answer:

D. 214 kPa

Explanation:

The absolute pressure is given by:

$p = p_a + p_g$

where

p is the absolute pressure

$p_a \sim 100 kPa$ is the atmospheric pressure

$p_g$ is the gauge pressure

In this problem, we have

$p_g = 114 kPa$

So, the atmospheric pressure is

$p = 100 kPa + 114 kPa = 214 kPa$

4 0

3 years ago

Read 2 more answers

A coil of wire with 50 turns lies in the plane of the page and has an initial area of 0.250 m2. The coil is now stretched to hav

Oxana [17]

Answer:

The induced emf in the coil is 170 volt and its direction is clockwise direction.

Explanation:

Given that,

Number of turns of a coil, N = 50

Initial area, $A_i=0.25\ m^2$

Final area, $A_f=0$

Time, t = 0.1 s

The magnetic field points into the page and has a strength of 1.36 T.

We need to find the magnitude and direction of the average value of the induced emf. Due to change in area of the coil and emf will be induced in it. The induced emf is given by :

$\epsilon=-N\dfrac{d\phi}{dt}\\\\\text{since}\ \phi=BA\\\\\epsilon=-N\dfrac{d(BA)}{dt}\\\\\epsilon=-NB\dfrac{A_f-A_i}{dt}\\\\\epsilon=-50\times 1.36\dfrac{0-0.25}{0.1}\\\\\epsilon=170\ V$

So, the induced emf in the coil is 170 volt and its direction is clockwise direction. Hence, this is the required solution.

3 0

3 years ago