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KiRa [710]
2 years ago
13

The air molecules around a candle flame are excited by the increased energy and spread out, decreasing in density and rising abo

ve the cooler, denser air around it. The denser air fills the space of the lighter air, continuing the cycle.
Which process is the passage describing?

A.radiation

B.subduction

C.conduction

D.convection
Physics
1 answer:
MAVERICK [17]2 years ago
3 0
The answer is b I believe
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Answer:

The change in momentum is 28265.71  kg-m/s.

Explanation:

Given that,

Mass of a car, m = 877 kg

Initial velocity of the car, u = 0 (at rest)

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Time, t = 0.951 s

We need to find the change in momentum produced by the force. It can be calculated as the difference of final momentum and the initial momentum.

\Delta P=m(v-u)\\\\=877\times (32.23-0)\\\\=28265.71\ kg-m/s

So, the change in momentum is 28265.71  kg-m/s.

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2 years ago
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Given:

L = 1 mH = 1\times 10^{-3} H

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