Answer:
100 ÷ 9.58 = 10.44 (approximate answer)
Answer:
none of the above
Explanation:
im pretty positive this is the answer tell me if i am wrong please
Answer:
0.532
Explanation:
Your equation to find the second bright interference maximum is gonna be this: d sin (Θ) = m λ
First, find your variables.
λ = 580 · 10^-9
d = 0.000125
m = 2
Next, fill in the equation.
d sin (θ) = m λ
(0.000125) sin (θ) = (2) (580·10^-9)
Then isolate your variable.
θ = arcsin ( (2)(580·10^-9) / (0.000125) )
Run your equation and you will end up with 0.53171246 , which rounds to 0.532.
The main thing you have to watch out for is make sure you are calculating for the bright interference and not the dark interference, as well as checking you're calculating for the maximum, not the minimum.
I hope this helps :D
Answer:
1.2 W
Explanation:
Let the value of resistance be R , emf of battery be E
current i = E / R
power = i² R
= E² x R / R²
= E² / R
Given
E² / R = .30
when two batteries are connected
Total emf = 2E
current = 2E / R
Power = ( 2E / R )² x R
= 4 E² / R
= 4 x .30
= 1.2 W .
