Electron arrangements is the most important and then the number of neutrons and protons !!!!
Answer:
97.2g
Explanation:
Step 1:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
Ca(OH)2 + 2HCl —> CaCl2 + 2H2O
Step 2:
Determination of the number of mole of water (H2O) to produce from the reaction.
This is illustrated below:
From the balanced equation above,
1 mole of Ca(OH)2 produced 2 moles of H2O.
Therefore, 2.70moles of Ca(OH)2 will produce = 2.7 x 2 = 5.4 moles of H2O.
Step 3:
Converting 5.4 moles of H2O to grams. This is illustrated below:
Number of mole of H2O = 5.4 moles
Molar Mass of H2O = (2x1) + 16 = 2 + 16 = 18g/mol
Mass of H2O =?
Mass = number of mole x molar Mass
Mass of H2O = 5.4 x 18
Mass of H2O = 97.2g
Therefore, 97.2g of water is produced from the reaction.
Answer:
Both graduated cylinders and beakers are pieces of laboratory glassware that have a specific function. Graduated cylinders typically are more accurate at reading the volumes of the liquid inside. Beakers are better for stirring and mixing liquids.
Flasks are notable for their unique shape: a rounded vessel and a cylindrical neck. The main differing characteristic between a flask and a beaker is that beakers have straight sides, rather than slanted sides like a flask. Beakers are mainly for measuring and transporting liquids from one site to the next.
Explanation:
hope this helps!!!!
Answer:
a) Mass of solution is 16,605 milli grams.
b) 57.29 grams is the mass of calcium chloride in 431.3 mL of a 12.0 wt% solution.
c) 1.1967 mol/L is the formal concentration of calcium chloride in 431.3 mL solution.
Explanation:
Mass by mass percentage of calcium chloride solution, wt% = 12.0%
Density of the solution = d = 1.107 g/mL
a) Volume of the solution , V= 15.0 mL
Mass of the solution = m
Mass of solution = 16.605 g = 16,605 mg (1g = 1000 mg)
b) Mass of the solution = m
Volume of the solution = V = 431.3 mL
Mass of calcium chloride = x
w% = 12.0%
57.29 grams is the mass of calcium chloride in 431.3 mL of a 12.0 wt% solution.
c) Moles of calcium chloride = 
V = Volume of the solution in Liters
n = 0.5161 mole
V = 431.3 mL = 0.4313 L
1.1967 mol/L is the formal concentration of calcium chloride in 431.3 mL solution.
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