Answer:
35.8 g
Explanation:
Step 1: Given data
Mass of water: 63.5 g
Step 2: Calculate how many grams of KCl can be dissolved in 63.5. g of water at 80 °C
Solubility is the maximum amount of solute that can be dissolved in 100 g of solute at a specified temperature. The solubility of KCl at 80 °C is 56.3 g%g, that is, we can dissolve up to 56.3 g of KCl in 100 g of water.
63.5 g Water × 56.3 g KCl/100 g Water = 35.8 g KCl
Answer:
T₂ = 43.46 °C
Explanation:
Given that:
The heat of the formation of carbon dioxide = - 393.5 kJ/mol (Negative sign suggests heat loss)
It means that energy released when 1 mole of carbon undergoes combustion = 393.5 kJ = 393500 J
Heat gain by water = Heat lost by the reaction
Thus,
For water:
Mass of water = 5100 g
Specific heat of water = 4.18 J/g°C
T₁ = 25 °C
T₂ = ?
Q = 393500 J
So,
T₂ = 43.46 °C
At constant temperature and pressure, increasing the amount of gas will increase the volume.
Hello!
This is a difficultly easy question, mostly because it seems like all of the answers would be right, but if I had to choose one, I would say (D) because this option gives the most detail.
Option A only tells us how fast a car was moving
Option B only tells us the rate the water falls and how fast it is going
Option C only tells how far and not the speed or destination
Option D is correct, it tells us the speed/rate, the destination, and what is moving
Therefore, Option (D) is correct
If this helps, please mark brainliest, have a great day!!
Using these Elements. Here would be the 4 ionic compounds.
CaF2
VF5
CaS
V2S5
