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igor_vitrenko [27]
3 years ago
15

why can we use P=VI in the question electric bulb base generator is rated 220 volts and 100W when it is operated on 110v what wi

ll be its power consumed?
Physics
1 answer:
MrRissso [65]3 years ago
8 0

Answer:

Correct answer:  P₂ = 25 W

Explanation:

Given: voltage V₁ = 220 V, power P₁ = 100 W, V₂ = 110 V, P₂ = ?

The formula for calculating power is:

P = V · I

We will include in the story and ohm's law:

I = V/R

We will replace the current in the expression for power

P = V · V/R = V²/R  ⇒ R = V²/P

We will first calculate the electrical resistance of the bulb which is a constant in the electrical circuit

R = V₁²/P₁ = 220²/ 100 = 48,400 / 100 = 484 Ω

Power consumption of bulb connected to 110 V is:

P₂ = V₂²/R = 110²/484 = 12,100/484 = 25 W

P₂ = 25 W

God is with you!!!

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3 years ago
Sam's job at the amusement park is to slow down and bring to a stop the boats in the log ride. If a boat and its riders have a m
shutvik [7]

Answer:

Sam will do 1152 J of work to stop the boat

Explanation:

Work: This is defined as the product of force and distance, the S.I unit of work is Joules. At any point in science, during calculation Energy and worked can be interchange because they have the same unit.

E = W = 1/2mv²................ Equation 1

Where E = energy, W = work, m = mass, v = velocity.

Given: m = 900 kg, v = 1.6 m/s

Substituting these values into equation 1

W = 1/2(900)(1.6)²

W = 450×2.56

W = 1152 J.

Therefore Sam will do 1152 J of work to stop the boat

7 0
3 years ago
A uniform ladder 5.0 m long rests against a frictionless, vertical wall with its lower end 3.0 m from the wall. The ladder weigh
dem82 [27]

Answer:

Explanation:

a )

Reaction force of the ground

R = mg

= 160 N

Maximum friction force possible

= μ x R

= μ x 160

= .4 x 160

= 64 N .

b )

 160 N will act at middle point . 740N will act at distance of 3 / 5 m from the wall ,

Taking moment about top point of ladder

160 x 1.5 + 740 x 3/5 + f x 4 = 900 x 3

240 + 444 + 4f = 2700

f = 504 N

c )

Let x be the required distance.  

Taking moment about top point of ladder

160 x 1.5 + 740 x 3 x / 5 + .4 x 900 x 4  = 900 x 3  ( .4 x 900 is the maximum friction possible )

240 + 444 x + 1440  = 2700

x = 2.3  m

so man can go upto 2.3 at which maximum friction acts .

8 0
3 years ago
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