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lilavasa [31]
3 years ago
15

How many calories you need per day to maintain your current weight.

Physics
1 answer:
Harman [31]3 years ago
3 0
Answer: adult males generally require 2,000-3000 calories per day, and adult females need 1,600-2,400.

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What is the net force needed to lift a full grocery sack weighing 210N uniformly?
Alex
If the sack weighs 210 newtons, then an upward force of 210 newtons
exactly cancels the downward force of gravity, and makes the net vertical
force on the bag zero. 

ANY upward force that's greater than 210 newtons makes the net force
act upward on the bag, and causes it to accelerate upward.
8 0
3 years ago
Current is constant at all points in a parallel circuit.<br><br> True<br> False
Sergio [31]
This is false. Current is the speed of the charge, 1 amp of current is 1 coulomb per second. So you can imagine the current of a circuit as the current of a river. In a parallel circuit, the river breaks into two separate streams. Some of the water goes down one river, some goes down the other. However, the total amount of water/coulombs never changes. This means that some of the total current will go down one river, and one the other. However, with less coulombs now the current will decrease. 

Long story short, since there are two paths, the charge will split and depending on the resistance of each parallel stream a different amount of charge will go down each branch.  
5 0
3 years ago
A janitor comes across a spilled substance on the floor of a highschool chemistry lab. he wants to make sure that the liquid is
MAVERICK [17]
A is the answer I think
5 0
4 years ago
Can someone help me please??<br> This question is confusing to me:(
puteri [66]
Its d. the water isn't moving the fish, and that's how they remain stationary. they don't have any currents pushing on them. if this is wrong, its c, which is practically the same thing. but its most likely d.
7 0
4 years ago
An incline plane has Ф = 40.0° and μ k = 0.15. Starting from rest, how long will it take a 4.0 kg block to reach a speed of 12 m
lesya [120]
     The block on the action of two forces, the Force of Friction and the Tangential Weight. Using the Newton's Secound Law, we have:

P_{t}-Fat=ma \\ mgsen\O-mgucos\O=ma \\ a=g(sen\O-ucos\O)
 
     Using the Velocity Hourly Equation, we get:

V=V_{o}+a\Delta t \\ \Delta t= \frac{V}{a}
 
     Uniting the equations:

\Delta t=  \frac{V}{g(sen\O-ucos\O)}
 
     Entering the unknowns:

\Delta t= \frac{V}{g(sen\O-ucos\O)} \\ \Delta t= \frac{12}{10(sen40^o-0.15cos^o)}  \\ \Delta t= \frac{12}{10(0,64-0.15x0.77)}  \\ \Delta t= \frac{12}{5.27}  \\ \boxed {\Delta t=2.28s}

Obs: Approximate results

If you notice any mistake in my english, please let me know, because i am not native.

5 0
3 years ago
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