Question

A 50 kg bobsled slides down an ice track

Answer 1

Hi there!

We can use the following kinematic equation:

$v_f^2 = v_i^2 + 2ad$

The initial velocity is 0 m/s, so:

$v_f^2 = 2ad$

vf = final velocity (? m/s)
a = acceleration due to gravity (g)
d = vertical height (m)

Plug in the givens and solve:

$v_f = \sqrt{2gd} = \sqrt{2(9.8)(173)} = \boxed{58.23 \frac{m}{s}}$