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VikaD [51]
2 years ago
6

A 50 kg bobsled slides down an ice track

Physics
1 answer:
STatiana [176]2 years ago
8 0

Hi there!

We can use the following kinematic equation:

v_f^2 = v_i^2 + 2ad

The initial velocity is 0 m/s, so:

v_f^2 = 2ad

vf = final velocity (? m/s)
a = acceleration due to gravity (g)
d = vertical height (m)

Plug in the givens and solve:

v_f = \sqrt{2gd} = \sqrt{2(9.8)(173)} = \boxed{58.23 \frac{m}{s}}

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