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alexira [117]
2 years ago
9

Which type of energy is the energy of motion (or movement)?

Physics
2 answers:
Tanya [424]2 years ago
8 0

Answer:

Kinetic energy

Kinetic energy is the motion of waves, electrons, atoms, molecules, substances, and objects.

Nat2105 [25]2 years ago
4 0
Kinetic energy is the motion of waves, electrons,atoms,molecules,substance,and object
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Calculate the internal axial load at a point D if length L=7 ft. The part is subjected to loads P1=632 lbs, P2=888 lbs (applied
liraira [26]

Answer:

- 256 lbs

Explanation:

The internal axial load at point D can be calculated as the change in the subjected loads. if the magnitude of the horizontal direction = zero

EF_x = 0; Then:

internal axial load at point D = Δ P

= -(P₂ - P₁)

= - ( 888 lbs - 632 lbs)

= - 256 lbs

5 0
3 years ago
How will heat flow between objects?
alukav5142 [94]
Without an external agent doing work, heat will always flow from a hotter to a cooler object. Two objects of different temperature always interact. There are three different ways for heat to flow from one object to another. They are conduction, convection, and radiation.
5 0
3 years ago
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Many biological systems are well-described by the laws of statistical physics. A simple yet often powerful approach is to think
GuDViN [60]

Answer:

z1/z2

Explanation:

we have no quantum effects therefore we can make use of Maxwell Boltzmann distribution in the description of this system.

using the boltzman distribution the probability of finding a particle in energy state

P_{ei}  = \frac{gie^{-ei/kol} }{z}

we have

gi to be degeneration of the ith state

ei to be energy of ith state

z=e^{-ei/kbt} summation

P_{ope} = \frac{e^{-ei/kBt} }{z} = \frac{Z_{1} }{Z}

We have R to be equal to

\frac{P_{ope} }{P_{Close} } = \frac{Z1}{Z2}

8 0
3 years ago
Real life examples of atomic physics
Flauer [41]

Answer:

magnets

static electricity

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7 0
3 years ago
Determine the stopping distances for a car with an initial speed of 88 km/h and human reaction time of 2.0 s for the following a
seropon [69]

Explanation:

Given that,

Initial speed of the car, u = 88 km/h = 24.44 m/s

Reaction time, t = 2 s

Distance covered during this time, d=24.44\times 2=48.88\ m

(a) Acceleration, a=-4\ m/s^2

We need to find the stopping distance, v = 0. It can be calculated using the third equation of motion as :

s=\dfrac{v^2-u^2}{2a}

s=\dfrac{-(24.44)^2}{2\times -4}

s = 74.66 meters

s = 74.66 + 48.88 = 123.54 meters

(b) Acceleration, a=-8\ m/s^2

s=\dfrac{v^2-u^2}{2a}

s=\dfrac{-(24.44)^2}{2\times -8}

s = 37.33 meters

s = 37.33 + 48.88 = 86.21 meters

Hence, this is the required solution.

4 0
3 years ago
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