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Lera25 [3.4K]
3 years ago
10

Joshua programs a robotic arm to place a block in a box by following the sequence of commands in the table. A 2-column table wit

h 4 rows. The first column labeled step has entries 1, 2, 3, 4. The second column labeled command has entries, grip block, lift block 10 centimeters, hold for 20 seconds, release block. During which step does the robotic arm do work on the block? Step 1 Step 2 Step 3 Step 4.
Physics
1 answer:
seraphim [82]3 years ago
5 0

Answer:

Step 2

Explanation:

Sorry I'm late

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Six automobiles are initially traveling at the indicated velocities. The automobiles have different masses and velocities. The d
KIM [24]

Answer:

a)Car E = Car D  > (Car F = Car B = Car C) > Car A

b)Car E = Car D  > (Car F = Car B = Car C) > Car A

Explanation:

Car A: mass = 500 kg; speed = 10 m/s

Car B: mass = 2000 kg;speed = 5 m/s

Car C:mass = 500 kg; speed = 20 m/s

Car D: mass = 1000 kg; speed = 20 m/s

Car E:mass = 4000 kg; speed = 5 m/s

Car F: mass = 1000 kg; speed = 10 m/s

Part a) Now we know that momentum of each car is product of mass and velocity , so we will have

<em>CarA:</em>

P_1 = m \times v\\P_1 = (500)(10)\\P_1 = 5 \times 10^3 kg m/s

<em>Car B:</em>

P_2 = m v\\P_2 = (2000)(5)\\P_2 = 10^4 kg m/s

Car C:

P_3 = m v\\P_3 = (500)(20)\\P_3 = 10^4 kg m/s

Car D:

P_4 = m v\\P_4 = (1000)(20)\\P_4 = 2\times 10^4 kg m/s

Car E:

P_5 = m v\\P_5 = (4000)(5)\\P_5 = 2\times 10^4 kg m/s

Car F:

P_6 = m v\\P_6 = (1000)(10)\\P_6 = 10^4 kg m/s

So the momentum is given as ,

Car E = Car D  > (Car F = Car B = Car C) > Car A

Part b)Impulse is given as change in momentum so here we can say that final momentum of all the cars will be zero as they all stops and hence the impulse is same as initial momentum of the car

so the order of impulse from largest to least is given as

Car E = Car D  > (Car F = Car B = Car C) > Car A

3 0
3 years ago
While rowing in a race, John uses his arms to exert a force of 155 N per stroke
Basile [38]

Answer:

Workdone = 2906.25J

Explanation:

Given the following data;

Force, F = 155

Distance, d = 0.75

Stroke, s = 25

Mathematically, work done is given by the formula;

Work done = force * distance * stroke

W = F * d * s

Where,

W is the work done

F represents the force acting on a body.

d represents the distance covered by the body.

s is the number of strokes.

Substituting into the equation, we have;

Workdone = 155*0.75*25

Workdone = 2906.25J

6 0
3 years ago
A 30 kg child rides a 20 kg bicycle. Together, the child and the bicycle have a momentum of 110 kg-m/s. What is the velocity of
love history [14]

Answer:

The velocity of the boy and the bicycle is 2.2 m/s.

Explanation:

We have,

Mass of child is 30 kg and the mass of bicycle is 20 kg. The combined momentum of the child and the bicycle is 110 kg-m/s.

It is required to find the velocity of the boy and the bicycle. The momentum of an object is given in terms of mass and its velocity. So,

p=Mv

M is combined mass of child and bicycle

v=\dfrac{p}{M}\\\\v=\dfrac{110}{30+20}\\\\v=2.2\ m/s

So, the velocity of the boy and the bicycle is 2.2 m/s.

8 0
3 years ago
What BAC is acceptable for teen drivers?
iragen [17]
If your talking about the blood alcohol content then there isn't a limit cause it would be underage drinking
7 0
3 years ago
Please help!!<br> Thanks!!
Igoryamba
B. 200 N to the left.

(The OTHER 100N to the left is cancelled out by the 100N to the right.)
4 0
3 years ago
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