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Lera25 [3.4K]
3 years ago
10

Joshua programs a robotic arm to place a block in a box by following the sequence of commands in the table. A 2-column table wit

h 4 rows. The first column labeled step has entries 1, 2, 3, 4. The second column labeled command has entries, grip block, lift block 10 centimeters, hold for 20 seconds, release block. During which step does the robotic arm do work on the block? Step 1 Step 2 Step 3 Step 4.
Physics
1 answer:
seraphim [82]3 years ago
5 0

Answer:

Step 2

Explanation:

Sorry I'm late

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Tin shear have longer handles than than the scissor used to cut cloth give reason​
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Describe two methods that can be used to cook eggs.​
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Thermopane window is constructed, using two layers of glass 4.0 mm thick, separated by an air space of 5.0 mm.
Bond [772]

To solve this problem it is necessary to apply the concepts related to rate of thermal conduction

\frac{Q}{t} = \frac{kA\Delta T}{d}

The letter Q represents the amount of heat transferred in a time t, k is the thermal conductivity constant for the material, A is the cross sectional area of the material transferring heat, \Delta T, T is the difference in temperature between one side of the material and the other, and d is the thickness of the material.

The change made between glass and air would be determined by:

(\frac{Q}{t})_{glass} = (\frac{Q}{t})_{air}

k_{glass}(\frac{A}{L})_{glass} \Delta T_{glass} = k_{air}(A/L)_{air} \Delta T_{air}

\Delta T_{air} = (\frac{k_{glass}}{k_{air}})(\frac{L_{air}}{L_{glass}}) \Delta T_{glass}

\Delta T_{air} = (\frac{0.84}{0.0234})(\frac{5}{4}) \Delta T_{glass}

\Delta T_{air} = 44.9 \Delta T_{glass}

There are two layers of Glass and one layer of Air so the total temperature would be given as,

\Delta T = \Delta T_{glass} +\Delta T_{air} +\Delta T_{glass}

\Delta T = 2\Delta T_{glass} +\Delta T_{air}

20\°C = 46.9\Delta T_{glass}

\Delta T_{glass} = 0.426\°C

Finally the rate of heat flow through this windows is given as,

\Delta {Q}{t} = k_{glass}\frac{A}{L_{glass}}\Delta T_{glass}

\Delta {Q}{t} = 0.84*24*10 -3*0.426

\Delta {Q}{t} = 179W

Therefore the correct answer is D. 180W.

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3 years ago
A solid of density 8000 kgm.. weighs 0.8 kgf in air. When it is completely
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Answer:<em> 0.5kg</em>

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