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Lera25 [3.4K]
2 years ago
10

Joshua programs a robotic arm to place a block in a box by following the sequence of commands in the table. A 2-column table wit

h 4 rows. The first column labeled step has entries 1, 2, 3, 4. The second column labeled command has entries, grip block, lift block 10 centimeters, hold for 20 seconds, release block. During which step does the robotic arm do work on the block? Step 1 Step 2 Step 3 Step 4.
Physics
1 answer:
seraphim [82]2 years ago
5 0

Answer:

Step 2

Explanation:

Sorry I'm late

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The following currents are measured in the same direction in a three-branch parallel circuit: 250 mA, 300 mA, and 800 mA. What i
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The current in the junction is 1350 mA or 1.350 A.

Explanation:

As per Kirchoff's first law, the algebraic sum of current meeting at any junction should be equal to the algebraic sum of current leaving the junction. As in the present case, three parallel branch circuit is given the current in 250 mA, 300 mA and 800 mA, respectively, the sum of these three current will be equal to the current in the junction.

So,

I₁+I₂+I₃ = I₄

So I₁,I₂ and I₃ are the current passed in the three parallel branches and I₄ is the current in the junction.

250 + 300 + 800 = 1350 mA

So the current in the junction is 1350 mA or 1.350 A.

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A small sphere of radius R is arranged to pulsate so that its radius varies in simple harmonic motion between a minimum of R−x a
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The intensity of the sound wave at a distance  is given by:

I = \frac{P_{total} }{4\pi d^{2} }

I = 4\pi R^{2}  \frac{ 2\pi^{2} f^{2} \rho B (\triangle R)^{2}}{\sqrt{\rho B} } * \frac{1}{4\pi d^{2} } \\I =   \frac{ 2\pi^{2}R^{2} f^{2}\sqrt{\rho B}(\triangle R)^{2}}{ d^{2} }

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