Answer:
The the empirical formula for magnesium chloride based on this experiment will be
Explanation:
Given that,
Mass of Mg = 0.50 g
Mass of magnesium chloride found = 1.99 g
Let the formula of magnesium chloride be
We know that,
Molar mass of Mg= 24 g/mol
Molar mass of magnesium chloride = (24x+35.5y) g/mol
We need to calculate the moles of Mg
Using formula of moles
Put the value into the formula
We need to calculate the mole of magnesium chloride
Using formula of moles
Put the value into the formula
The reaction will be,
We need to calculate the value of x and y
Using number of moles of Mg in reactant and product
Moles of Mg atom in reactant=Moles of Mg atom in product
Hence, The the empirical formula for magnesium chloride based on this experiment will be
Answer:
Explanation:
Iodine - 125
The atomic symbol of iodine is ¹²⁵₅₃ I
The symbol for iodine is I
The atomic number of iodine is 53,
and the atomic mass of iodine is 125 .
<u>The representation of the atomic symbol is as, the atomic mass is written in uppercase and the atomic number is written in lower case , followed by the symbol of the element .</u>
Iodine is a radio active element , used for many biological process .
It is the second largest -lived radioisotope of iodine .
The first is iodine-129 .
The Atomic number of an element depends upon how many protons and nuetrons are in the element.To find the atomic mass you need to add the protons and nuetrons together
Answer:
Explanation:
According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.
The balanced equation will be:
Answer:
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