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1 year ago

Help pls quick!!

Physics

2 answers:

Mazyrski [523]1 year ago

7 0

Answer:

Answer is C

Explanation:

borishaifa [10]1 year ago

3 0

Answer:

Explanation:

I hade the same assignment and the answer was C

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Un hamster esta sentado sobre un tocadisco cuya rapidez angular es constante si el hamster se mueve a un punto localizado al dob

kotegsom [21]

Answer:

b) se duplica

Explanation:

The disk is moving with constant angular velocity, let's call it $\omega$ .

The linear velocity of a point on the disk is given by

$v=\omega r$

where r is the distance of the point from the axis of rotation.

In this problem, the object is moved at a distance twice as far as the initial point, so

$r' = 2r$

Therefore, the new linear velocity is

$v'=\omega r' = \omega (2r) = 2 \omega r = 2 v$

So, the velocity has doubled, and the correct answer is

b) se duplica

8 0

2 years ago

A person's center of mass is very near the hips, at the top of the legs. Model a person as a particle of mass mm at the top of a

muminat

Answer:

$\mathbf{v_{max} = \sqrt{gL}}$

Explanation:

Considering an object that moving about in a circular path, the equation for such centripetal force can be computed as:

$\mathbf {F = \dfrac{mv^2}{2}}$

The model for the person can be seen in the diagram attached below.

So, along the horizontal axis, the net force that is exerted on the person is:

$mg cos \theta = \dfrac{mv^2}{L}$

Dividing both sides by "m"; we have :

$g cos \theta = \dfrac{v^2}{L}$

Making "v" the subject of the formula: we have:

$v^2 = g Lcos \theta$

$v=\sqrt{ gL cos \theta$

So, when $\theta$ = 0; the velocity is maximum

∴

$v_{max} = \sqrt{gL \ cos \theta}$

$v_{max} = \sqrt{gL \ cos (0)}$

$v_{max} = \sqrt{gL \times 1}$

$\mathbf{v_{max} = \sqrt{gL}}$

Hence; the maximum walking speed for the person is $\mathbf{v_{max} = \sqrt{gL}}$

3 0

2 years ago

The 300 m diameter Arecibo radio telescope is observing the Andromeda galaxy at a wavelength of 29 cm. show answer No Attempt 50

jekas [21]

Answer:

The angle between two just-resolvable stars for the Arecibo telescope is $1.179x10^{-3}rad$ .

Explanation:

The resulting image in a telescope obtained from an object is a diffraction pattern.

That diffraction pattern is obtained because the light encounters different obstacles on its path inside the telescope (interact with the walls and edges of the instrument).

The diffraction pattern is composed by a central disk, called Airy disk, and diffraction rings.

The angular resolution is defined as the minimal separation at which two sources can be resolved one for another, or in other words, when the distance between the two diffraction patterns maxima is greater than the radius of the Airy disk.

The angular resolution can be determined in an analytical way by means of the Rayleigh criterion.

$\theta = 1.22\frac{\lambda}{D}$ (1)