Answer:
co+ o2+ 2co2 is not balanced reaction
Answer:
6 orbitals
Explanation:
you take the total number of orbitals there would normally be and add that to three and you get a total of 6 orbitals in axial.
Answer : The equilibrium concentration of 
is, 0.50 M
Explanation : Given,
Initial moles of = 0.65 mole
Volume of solution = 1.0 L
Moles of 
at equilibrium = 0.15 mole
The balanced equilibrium reaction will be,
Initial moles 0.65 0 0
At eqm. (0.65-x) x x
Moles of at equilibrium = x = 0.15 mole
Moles of 
at equilibrium = x = 0.15 mole
Moles of at equilibrium = (0.65-x) = (0.65-0.15) = 0.50 mole
Now we have to calculate the concentration of 
at equilibrium.
Formula used : 
Therefore, the equilibrium concentration of is, 0.50 M
Answer:
V₂ = 3227.46 L
Explanation:
Given data:
Initial volume of gas = 1000 L
Initial temperature = 50°C (50 +273 = 323 K)
Initial pressure = 101.3 KPa
Final pressure = 27.5 KPa
Final temperature = 10°C (10 +273 = 283 K)
Final volume = ?
Solution:
According to general gas equation:
P₁V₁/T₁ = P₂V₂/T₂
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 101.3 KPa × 1000 L × 283 K / 323 K × 27.5 KPa
V₂ = 28667900 KPa .L. K /
8882.5 K.KPa
V₂ = 3227.46 L
