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hram777 [196]
2 years ago
9

on takeoff, the propellers on a uav (unmanned aerial vehicle) increase their angular velocity from rest at a rate of ω = (25.0t)

rad/s for 3.0 s. (a) what is the instantaneous angular velocity of the propellers at t = 2.0 s? (b) what is the angular acceleration?​
Physics
1 answer:
Rudik [331]2 years ago
7 0

Hi there!

a)
We can find the angular velocity at t = 2.0 s by plugging in this value into the equation.

\omega (t) = 25.0t \\\\\omega (2) = 25.0(2) = \boxed{50.0 \frac{rad}{s}}

b)

The angular acceleration is the derivative of the angular velocity, so:
\alpha (t) = \frac{d\omega}{dt} (25.0t) = 25.0

Thus, the angular acceleration is a <u>constant 25 rad/s².</u>

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The given data is as follows.

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                x = \frac{W_{b} \times 1.5}{W_{s}}

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