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BlackZzzverrR [31]
3 years ago
6

A lower ramp will be longer, allowing for less force to be used, but makes an object travel a greater distance.

Physics
2 answers:
olasank [31]3 years ago
8 0

Answer: READ WHOLE THING ***

A ramp is an example of an inclined plane. Think back to the example of the ramp and the moving truck. The ramp reduced the amount of force needed to lift the box by moving it over a greater distance. The longer an inclined plane, the less force is required to move an object upward.

Hope this helps :)

ryzh [129]3 years ago
4 0

Answer:

this is true, but if you want your object to go faster you have to have the ramp at a higher point, and it will go faster and possibly go further because of its speed. it just depends what the mass of the object is and how low the ramp is.

Explanation:

hope this helps brainliest please <3

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Explanation:

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3 0
3 years ago
Which of newton's laws explains why your hands get red when you press them hard against a wall
kirill115 [55]
The Newton’s law that explains why the hands get red when you press them hard against a wall is Newton’s third law. When one body exerts a force on a second body, the second body simultaneously exerts a force equal in magnitude and opposite direction on the first body.
5 0
3 years ago
Two 110 kg bumper cars are moving toward each other in opposite directions. Car A is moving at 8 m/s and Car Z at –10 m/s when t
salantis [7]

Explanation:

Mass of bumper cars, m_1=m_2=110\ kg

Initial speed of car A, u_1=8\ m/s

Initial speed of car Z, u_2=-10\ m/s

Final speed of car A after the collision, v_1=-10\ m/s

We need to find the velocity of car Z after the collision. Let it is equal to v_2. Using the conservation of momentum as :

m_1u_1+m_2u_2=m_1v_1+m_2v_2

110\times 8+110\times (-10)=110\times (-10)+110v_2

v_2=\dfrac{-1320}{110}\ m/s

v_2=-12\ m/s

So, the velocity of car Z after the collision is (-12 m/s). Hence, this is the required solution.

5 0
3 years ago
What is the energy of a photon whose frequency is 6.0 x 10^20?
omeli [17]

Answer:

3.75 MeV

Explanation:

The energy of the photon can be given in terms of frequency as:

E = h * f

Where h = Planck's constant

The frequency of the photon is 6 * 10^20 Hz.

The energy (in Joules) is:

E = 6.63 x10^(-34) * 6 * 10^(20)

E = 39.78 * 10^(-14) J = 3.978 * 10^(-13) J

We are given that:

1 eV = 1.06 * 10^(-19) Joules

This means that 1 Joule will be:

1 J = 1 / (1.06 * 10^(-19)

1 J = 9.434 * 10^(18) eV

=> 3.978 * 10^(-13) J = 3.978 * 10^(-13) * 9.434 * 10^(18) = 3.75 * 10^(6) eV

This is the same as 3.75 MeV.

The correct answer is not in the options, but the closest to it is option C.

6 0
3 years ago
Substances released into the air are known as
irakobra [83]

Your answer is Emissions

3 0
3 years ago
Read 2 more answers
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